Php 将mysql查询转换为雄辩的查询生成器

所以我在Laravel Elount query builder中编写mysql查询时遇到了麻烦。这是mysql查询

SELECT a.Location, a.AptDate, a.AptTime, IF(a.AptStatus = 3, 500, AptLength) AptLength,
a.AptStatus, o.opname, a.OperatoryNum
FROM schedules a
LEFT JOIN ops o ON a.Location = o.location AND (a.Operatory = o.opname OR a.AptStatus = 3)

这就是我到目前为止所做的，但它不起作用，因为我得到了一个错误，我的语法有一个错误

$arrAppointment = DB::table('schedules a')
                                ->select("a.Location, a.AptDate, a.AptTime",
                                    DB::raw('IF(a.AptStatus = 3, 500, AptLength)'), 'AptLength,a.AptStatus, o.opname, a.OperatoryNum' )
                                ->leftJoin('ops o', 'a.Location = o,location AND a.Operatory = o.opname or a.AptStatus = 3')

---

你知道我哪里出错了吗？

我看到左连接上有语法错误（

o，location

=>

o.location

），但无论如何，请尝试以下操作：

$arrAppointment = DB::table('schedules a')
->selectRaw('a.Location, a.AptDate, a.AptTime, IF(a.AptStatus = 3, 500, AptLength) AptLength,a.AptStatus, o.opname, a.OperatoryNum' )
->leftJoin(DB::raw('ops as o'), function($join) {
    $join->on('a.Location', '=', 'o.location');
    $join->where(function($q) {
        $q->where('a.Operatory','=','o.opname');
        $q->orWhere('a.AptStatus','=', 3);
    });
});