Php 按天按周分组获取最近4周的记录

我需要一个查询，它允许我从MySQL表中选择最近4周的数据，但是从4周前的星期一开始输出为天，而不考虑一周中的当前日期

DB有一个用户表，一个活动表，它有一个userID的FK。 具有FK到activityID的activityStats表

查询将用于创建类似以下内容的数组：

$array = [
   "userid" => "userid",
   "dateAdded" => "dateAdded",
   "week1" => $array = [
      "monday" => $array = [
         "activityid" => "1",
         "time" => "21",
         ...
      ]
      "tuesday" => $array = [
         "activityid" => "2",
         "time" => "16",
         ...
      ]
      "wednesday" => $array = [
         "activityid" => "3",
         "time" => "16",
         ...
      ]
      ...
   "week2" => $array = [
      "monday" => $array = [
         "activityid" => "8",
         "time" => "21",
         ...
      ]
      "tuesday" => $array = [
         "activityid" => "9",
         "time" => "16",
         ...
      ]
      "wednesday" => $array = [
         "activityid" => "10",
         "time" => "16",
         ...
      ]
      ...
   ]
   ...
];

我可以创建多个查询来实现这一点，但可能需要10周或52周的时间，单独的查询可能无法解决这一问题

---

不知道从何处开始。

假设时间戳列被称为

timestamp

，您可以：

选择CONCAT（年（时间戳），“/”，周（时间戳））作为周

然后检索特定范围、按周排序等