Php Laravel雄辩的嵌套“;如果不在“中”;联接查询
我无法从SQL异常编写适当的雄辩查询。我雄辩的查询返回错误。 以下是SQL异常:Php Laravel雄辩的嵌套“;如果不在“中”;联接查询,php,laravel,laravel-eloquent,nested-queries,Php,Laravel,Laravel Eloquent,Nested Queries,我无法从SQL异常编写适当的雄辩查询。我雄辩的查询返回错误。 以下是SQL异常: SELECT * FROM `candidate_infos` JOIN training_infos on candidate_infos.id = training_infos.candi_id where candidate_infos.mdl_id=1 and candidate_infos.id not in ( (SELECT candi_id FROM training_infos WHERE
SELECT * FROM `candidate_infos`
JOIN training_infos on candidate_infos.id = training_infos.candi_id
where candidate_infos.mdl_id=1
and candidate_infos.id not in ( (SELECT candi_id FROM training_infos WHERE
candi_id in (1,5,6,8) ))
我试过这个:
DB:: table('candidate_infos')
->join('training_infos','candidate_infos.id', '=', training_infos.candi_id')
->where('candidate_infos.mdl_id', $value->mdl_id)
->where('candidate_infos.id', 'not in', select(DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)")))
->get();
试试这个
DB:: table('candidate_infos')
->join('training_infos','candidate_infos.id', '=', 'training_infos.candi_id')
->where('candidate_infos.mdl_id', $value->mdl_id)
->whereNotIn('candidate_infos.id', DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)"))
->get();
你应该试试这个:
$resltQueries = DB::select(DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)"));
$arrQuery = array();
foreach($resltQueries as $key => $resltQuery){
$arrQuery[$key] = $resltQuery;
}
DB:: table('candidate_infos')
->join('training_infos','candidate_infos.id', '=', 'training_infos.candi_id')
->where('candidate_infos.mdl_id', $value->mdl_id)
->whereNotIn('candidate_infos.id', $arrQuery)
->get();
只需跳过子查询并使用
和training_infos.candi_id NOT IN(1,5,6,8)
我们可以查看您的表结构吗?