Php Laravel雄辩的嵌套“;如果不在“中”;联接查询

Php Laravel雄辩的嵌套“;如果不在“中”;联接查询,php,laravel,laravel-eloquent,nested-queries,Php,Laravel,Laravel Eloquent,Nested Queries,我无法从SQL异常编写适当的雄辩查询。我雄辩的查询返回错误。 以下是SQL异常: SELECT * FROM `candidate_infos` JOIN training_infos on candidate_infos.id = training_infos.candi_id where candidate_infos.mdl_id=1 and candidate_infos.id not in ( (SELECT candi_id FROM training_infos WHERE

我无法从SQL异常编写适当的雄辩查询。我雄辩的查询返回错误。 以下是SQL异常:

SELECT * FROM `candidate_infos` 
JOIN training_infos on candidate_infos.id = training_infos.candi_id 
where candidate_infos.mdl_id=1
and candidate_infos.id not in ( (SELECT candi_id FROM training_infos WHERE 
candi_id in (1,5,6,8) ))
我试过这个:

DB:: table('candidate_infos')
    ->join('training_infos','candidate_infos.id', '=', training_infos.candi_id')
    ->where('candidate_infos.mdl_id', $value->mdl_id)
    ->where('candidate_infos.id', 'not in', select(DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)")))
    ->get();
试试这个

DB:: table('candidate_infos')
->join('training_infos','candidate_infos.id', '=', 'training_infos.candi_id')
->where('candidate_infos.mdl_id', $value->mdl_id)
->whereNotIn('candidate_infos.id', DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)"))
->get();
你应该试试这个:

$resltQueries = DB::select(DB::raw("SELECT candi_id FROM training_infos WHERE candi_id in ($value->cadi_ids)"));
$arrQuery = array();

foreach($resltQueries as $key => $resltQuery){
  $arrQuery[$key] = $resltQuery;
}

DB:: table('candidate_infos')
  ->join('training_infos','candidate_infos.id', '=', 'training_infos.candi_id')
  ->where('candidate_infos.mdl_id', $value->mdl_id)
  ->whereNotIn('candidate_infos.id', $arrQuery)
  ->get();

只需跳过子查询并使用
和training_infos.candi_id NOT IN(1,5,6,8)
我们可以查看您的表结构吗?