使用PHP存储单击的链接数据并将其传输到新页面

我正在创建一个web应用程序，允许学生通过HTML表单注册（完成此部分），并将其数据存储在DB中（完成）。我正在使用PHP/MYSQL来写这篇文章

我的想法是，我有一个'后端'将允许管理员搜索一个学生的第一，最后，或全名（这已完成），并显示在下一页的学生名单。（也已完成）。学生名单将是个人超链接

我的页面布局是：

backendhome.php

 <?php
    $query = $_POST['query']; //gets value sent over from search 
     $query = htmlspecialchars($query); 
        // changes characters used in html to their equivalents, for example: < to &gt;

        $query = mysql_real_escape_string($query);
        // makes sure nobody uses SQL injection

        $raw_results = mysql_query("SELECT * FROM students
            WHERE (`firstName` LIKE '%".$query."%') OR (`lastName` LIKE '%".$query."%')") or die(mysql_error());

  if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

            while($results = mysql_fetch_array($raw_results)){
            // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop
                echo "<a href='studentData.php'>".$results['firstName']." ".$results['lastName']."</a></br>";
                // posts results gotten from database you can also show id ($results['id'])
            }

        }
        else{ // if there is no matching rows do following
            echo "No results";
        }
  ?>

• 有搜索栏和搜索按钮

search.php

• 单击搜索时，将执行此页面，该页面将获取搜索的项目并在数据库中找到该项目

• 吐出所有名/姓/全名学生的数据（可能是多个学生）-这些是超链接

我在search.php上使用的代码段搜索方法

 <?php
    $query = $_POST['query']; //gets value sent over from search 
     $query = htmlspecialchars($query); 
        // changes characters used in html to their equivalents, for example: < to &gt;

        $query = mysql_real_escape_string($query);
        // makes sure nobody uses SQL injection

        $raw_results = mysql_query("SELECT * FROM students
            WHERE (`firstName` LIKE '%".$query."%') OR (`lastName` LIKE '%".$query."%')") or die(mysql_error());

  if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

            while($results = mysql_fetch_array($raw_results)){
            // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop
                echo "<a href='studentData.php'>".$results['firstName']." ".$results['lastName']."</a></br>";
                // posts results gotten from database you can also show id ($results['id'])
            }

        }
        else{ // if there is no matching rows do following
            echo "No results";
        }
  ?>

---

您可以按如下所述传递您的学生id，并在studentData.php页面中获取该
id
，然后检索学生信息并显示它

echo "<a href='studentData.php?id=".$results['id']."'>".$results['firstName']." ".$results['lastName']."</a></br>";
                         .......^

echo“
”；
.......^
非常感谢您！这起作用了。我提取了url，然后使用子字符串来获取我的id。现在我可以继续这个项目了！