Php 使用表单编辑数据

我正在尝试编辑数据库中的数据，但无法使其正常工作

我尝试将脚本分解为基本部分，并对每个部分进行故障排除

“删除”按钮工作正常，但编辑数据却不行

我哪里出错了

我的结构 数据库=域表=域\u信息行=域

<?php include("header.php");

//include database connection
include 'db_connect.php';

$action = isset( $_POST['action'] ) ? $_POST['action'] : "";
if($action == "update"){
//write query
$query = "update domains_info 
set
domain = '".$mysqli->real_escape_string($_POST['domain'])."', 
where id='".$mysqli->real_escape_string($_REQUEST['id'])."'";

if( $mysqli->query($query) ) {
    echo "User was updated.";
}else{
    echo "Database Error: Unable to update record.";
}
}
if($action=='delete'){ //if the user clicked ok, run our delete query

$query = "DELETE FROM domains_info WHERE id='".$mysqli->real_escape_string($_GET['id'])."'";
if( $mysqli->query($query) ){
    echo "User was deleted.";
}else{
    echo "Database Error: Unable to delete record.";
}}

$query = "select id, domain
            from domains_info
            where id='".$mysqli->real_escape_string($_REQUEST['id'])."'
            limit 0,1";

$result = $mysqli->query( $query );
$row = $result->fetch_assoc();

$id = $row['id'];
$domain = $row['domain'];?>

<form action='#' method='post' border='0' class="well form-horizontal">
  <fieldset>
    <label class="control-label" for="name">Domain</label>
    <div class="controls">
    <input id="name" type="text" name="name" value="<?php echo$domain; ?>">
    <input type='hidden' name='id' value='<?php echo $id ?>' />

    <!-- we will set the action to edit -->
    <input type='hidden' name='action' value='update' />
    <input type='submit' value='Edit' />
  </fieldset>
</form>
<?php echo "<a href='#' onclick='delete_user( {$id} );'>Delete</a>"; ?> 
<script type='text/javascript'>

function delete_user( id ){
//prompt the user
var answer = confirm('Are you sure you want to delete <?php echo$name; ?>?');

if ( answer ){ //if user clicked ok
//redirect to url with action as delete and id of the record to be deleted
window.location = 'deletecontact.php?id=' + id;
} 
}
</script>

---

更新查询中有一个额外的“，”

 $query = "update domains_info 
 set
 domain = '".$mysqli->real_escape_string($_POST['domain'])."', 
 where id='".$mysqli->real_escape_string($_REQUEST['id'])."'";

与

---

它会给出一个MySQL错误吗？尝试添加

printf（“错误消息：%s\n”，$mysqli->error）下面
echo“数据库错误：无法更新记录。”在UPDATE语句中，
domain=
行的末尾有一个额外的逗号。如果您使用
$mysqli->error
，它将准确地告诉您问题所在；检查与您的MySQL服务器版本对应的手册，了解第4行“where id='2”附近使用的正确语法。如果您使用准备好的语句，您不必为真正的_escape_字符串而烦恼。如果我要在此添加另一行，会是什么？如果我要在此添加另一行，会是什么？
 $query = "update domains_info 
 set
 domain = '".$mysqli->real_escape_string($_POST['domain'])."', 
 where id='".$mysqli->real_escape_string($_REQUEST['id'])."'";

 $query = "update domains_info 
 set
 domain = '".$mysqli->real_escape_string($_POST['domain'])."' 
 where id='".$mysqli->real_escape_string($_REQUEST['id'])."'";