Php 如何基于路径样式值创建数组树？

我对多维数据数组有一个问题。我有这样一个数据数组：

[
    [
        "name" => "netSnmp",
        "oid" => "1.3.6.1.4.1.8072"
        "status" => "current"
    ], [
        "name" => "netSnmpObjects",
        "oid" => "1.3.6.1.4.1.8072.1"
    ], [
        "name" => "netSnmpEnumerations",
        "oid" => "1.3.6.1.4.1.8072.3"
    ], [
        "name" => "netSnmpModuleIDs",
        "oid" => "1.3.6.1.4.1.8072.3.1"
    ], [
        "name" => "netSnmpAgentOIDs",
        "oid" => "1.3.6.1.4.1.8072.3.2"
    ], [
        "name" => "netSnmpDomains",
        "oid" => "1.3.6.1.4.1.8072.3.3"
    ], [
        "name" => "netSnmpNotificationPrefix",
        "oid" => "1.3.6.1.4.1.8072.4"
    ], [
        "name" => "netSnmpNotifications",
        "oid" => "1.3.6.1.4.1.8072.4.0"
    ], [
        "name" => "netSnmpNotificationObjects",
        "oid" => "1.3.6.1.4.1.8072.4.1"
    ]
]

我正在寻找一种基于上面数组中的

oid

值创建数组树的简单方法。那些

oid

值是点分隔的路径。部分越多，对应项在最终树中放置的越深

所需输出：

[
    "text" => "netSnmp",
    "oid" => "1.3.6.1.4.1.8072",
    "nodes" => [
        [
            "oid" => "1.3.6.1.4.1.8072.1",
            "text" => "netSnmpObjects"
        ], [
            "oid" => "1.3.6.1.4.1.8072.3",
            "text" => "netSnmpEnumerations",
            "nodes" => [
                [
                    "text" => "netSnmpModuleIDs",
                    "oid" => "1.3.6.1.4.1.8072.3.1"
                ], [
                    "text" => "netSnmpAgentOIDs",
                    "oid" => "1.3.6.1.4.1.8072.3.2"
                ], [
                    "text" => "netSnmpDomains",
                    "oid" => "1.3.6.1.4.1.8072.3.3"
                ]
            ]
        ], [
            "oid" => "1.3.6.1.4.1.8072.4",
            "text" => "netSnmpNotificationPrefix"
            "nodes" => [
                [
                    "text" => "netSnmpNotifications",
                    "oid" => "1.3.6.1.4.1.8072.4.0"
                ], [
                    "text" => "netSnmpNotificationObjects",
                    "oid" => "1.3.6.1.4.1.8072.4.1"
                ]
            ]
        ]
    ]
]

---

你知道怎么解决吗？

你可以通过

oid

在一个新的关联数组中为你的数据设置密钥：这样你就可以快速地查找某个父密钥

然后，只需获取任意给定键的父键（切掉最后一个点分隔的部分）并查看它在新关联数组中的位置，然后将其附加到其

节点

数组

下面是一个函数，用于：

function makeTree($arr) {
    $keyed = [];
    foreach ($arr as $item) $keyed[$item["oid"]] = $item;
    $root = null;
    
    foreach ($keyed as &$item) {
        $key = $item["oid"];
        $parent = substr($key, 0, strrpos($key, "."));
        if (isset($keyed[$parent])) {
            $keyed[$parent]["nodes"][] =& $item;
        } else {
            $root = $key;
        }
    }
    return $keyed[$root];
}

您可以在示例数据上这样运行它：

$arr = [
    [
        "name" => "netSnmp",
        "oid" => "1.3.6.1.4.1.8072",
        "status" => "current"
    ], [
        "name" => "netSnmpObjects",
        "oid" => "1.3.6.1.4.1.8072.1"
    ], [
        "name" => "netSnmpEnumerations",
        "oid" => "1.3.6.1.4.1.8072.3"
    ], [
        "name" => "netSnmpModuleIDs",
        "oid" => "1.3.6.1.4.1.8072.3.1"
    ], [
        "name" => "netSnmpAgentOIDs",
        "oid" => "1.3.6.1.4.1.8072.3.2"
    ], [
        "name" => "netSnmpDomains",
        "oid" => "1.3.6.1.4.1.8072.3.3"
    ], [
        "name" => "netSnmpNotificationPrefix",
        "oid" => "1.3.6.1.4.1.8072.4"
    ], [
        "name" => "netSnmpNotifications",
        "oid" => "1.3.6.1.4.1.8072.4.0"
    ], [
        "name" => "netSnmpNotificationObjects",
        "oid" => "1.3.6.1.4.1.8072.4.1"
    ]
];

$result = makeTree($arr);
print_r($result);

---

那么到底是什么问题呢？在这个例子中，对事物进行分组的标准是什么？谢谢@Mihail Minkov，我想根据oid值进行树状排列。请使用oid的树状层次规则更新您的问题，这样对人们理解问题会更有用。这个函数工作得很好，现在我可以根据我的需要开发它。非常感谢你的帮助。