PHP/MySQL:SyntaxError:JSON.parse:JSON数据第1行第1列的意外字符
我有一张MySQL表:PHP/MySQL:SyntaxError:JSON.parse:JSON数据第1行第1列的意外字符,php,mysql,json,pdo,Php,Mysql,Json,Pdo,我有一张MySQL表: mysql> select * from members; +-------+-----------+-----------+ | memid | firstname | lastname | +-------+-----------+-----------+ | 1 | billal | begueradj | | 2 | bill | gates | | 3 | steve | jobs |
mysql> select * from members;
+-------+-----------+-----------+
| memid | firstname | lastname |
+-------+-----------+-----------+
| 1 | billal | begueradj |
| 2 | bill | gates |
| 3 | steve | jobs |
+-------+-----------+-----------+
3 rows in set (0.00 sec)
我有以下代码:
<?php
$output = array('error' => false);
$members = array();
try {
$db = new PDO('mysql:host=localhost;dbname=bill;charset=utf8',
'root',
''
);
} catch(Exception $e) {
die('Error in connecting to DB: <br/>'.$e->getMessage());
}
$response = $db->query('SELECT * FROM members');
while($row = $response->fetch()){
echo $row['firstname'].' ';
echo $row['lastname'].'<br/>';
array_push($members, $row);
}
$output['members'] = $members;
$response->closeCursor();
$json = json_encode($out);
echo $json; // outputs correctly
header("Content-type: application/json"); // error here
die();
?>
仍然会收到相同的错误消息请尝试此操作,它可能会帮助您解决此问题
if ($response->num_rows > 0) {
while($row[] = $response -> fetch_assoc()) {
$item = $row;
$json = json_encode($item);
}
}
header()
应该放在所有输出之上,所以在回显任何内容之前
另外,由于您没有将整个内容编码为JSON,而只是部分内容,我猜您缺少JSON的开头和结尾
正确的JSON输出:
例1:
例2:
PHP:
你真的回显了json吗?所以在header()
行之后,你尝试了回显$json代码>出现错误?您尝试了ehco
而没有echo
^噢。。。是的,对不起。。。现在它输出正确,但错误仍然存在,将echo
放在header()
行之后。这与我在问题中发布的错误消息相同
if ($response->num_rows > 0) {
while($row[] = $response -> fetch_assoc()) {
$item = $row;
$json = json_encode($item);
}
}
{
"key1": "value1",
"key2": "value2",
"key3": "value3"
}
[
{
"key1": "value1",
"key2": "value2",
"key3": "value3"
},
{
"key1": "value1",
"key2": "value2",
"key3": "value3"
},
{
"key1": "value1",
"key2": "value2",
"key3": "value3"
}
]
<?php
$output = ["error" => false, "members" => []];
try {
$db = new PDO("mysql:host=localhost;dbname=bill;charset=utf8", "root", "");
} catch(Exception $e) {
die("Error in connecting to DB: <br/>{$e->getMessage()}");
}
$response = $db->query("SELECT * FROM members");
while($row = $response->fetch(PDO::FETCH_ASSOC)) {
array_push($output["members"], $row);
}
$response->closeCursor();
$json = json_encode($output);
header("Content-type: application/json");
echo $json;