PHP表单-上传图像，将头像放置在新闻文章的评论功能上

试图制作一个简单的脚本来评论一篇新闻文章，它的文本工作，但我希望用户能够提交一个图像作为图标或化身使用。这是表单字段：

             <form action= "../create_comment.php" method="post" name="comments_form" enctype="multipart/form-data">
            <div>
              <label>Name<span>*</span></label>
              <input name="name" type="text" value=" ">
            </div>
            <div>
              <label>Email<span>*</span></label>
              <input name="email" type="text" value=" ">
            </div>
            <div>
              <label>Your Comment<span>*</span></label>
              <textarea name="comment"> </textarea>
            </div>
            <div>
            <label>Add your avatar<span>*</span></label>
            <input name="file" type="file"  />
            <div>
            <input name="storyid" value="192837465" type="hidden">
            <input name="page_path" value="777776" type="hidden">
            <input type="submit" value="submit">
          </form>

名字*
电子邮件*
你的评论*
添加你的头像*

表单指向这个脚本：

    <?php
    $formats = array("gif", "jpeg", "jpg", "png");
    $temp = explode(".", $_FILES["file"]["name"]);
    $extension = end($temp);
    if ( $_FILES["file"]["size"] < 90000 && in_array($extension, $formats) ) {
        if ($_FILES["file"]["error"] > 0) {
            // something went wrong, display the error using; $_FILES["file"]["error"];
        } else {
            if ( !file_exists("avatars/" . $_FILES["file"]["name"] ) ) {
                move_uploaded_file($_FILES["file"]["tmp_name"], "avatars/" . $_FILES["file"]["name"]);
            }
        }
    }
    $tempLink = "http://www.website.com/avatars/" . $_FILES["file"]["name"];
    $page_path = $_POST['page_path'];
    $con=mysqli_connect
    ("","","","");
     // Check connection
     if (mysqli_connect_errno())
       {
       echo "Failed to connect to MySQL: " . mysqli_connect_error();
       }
     $sql="INSERT INTO comments (name, comment, email, storyid, entry_date)
     VALUES
     ('$_POST[name]','$_POST[comment]','$_POST[email]','$_POST[storyid]',now())";
     if (!mysqli_query($con,$sql))
       {
       die('Error: ' . mysqli_error($con));
       }
    header('Location: http://www.website.com/' . $page_path);
    mysqli_close($con);
    ?>

格式的html添加

<form action="" method="post" enctype="multipart/form-data">


是否已将表单属性enctype设置为“multipart/form data”？将enctype=“multipart/form data”放在表单标记中。请编辑您的问题，以显示代码中的开始表单标记添加enctype已起作用！我发誓你们中的一些人正在注意可能的重复