mysql assoc_数组的PHP函数

在一个新项目中，我试图通过将大多数操作存储为函数来减少重复代码，从而提高我的技能

以前我所有的代码都在每个PHP文件的头中（一种la Dreamweaver风格）

在这个新项目中，我有一个页面需要拉一个关联数组来显示博客

它目前正在失败。以下是我所拥有的：

DB.php

<?php
$servername = "localhost";
$username = "USERNAME";
$password = "*******";
$dbname = "dbname";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
?> 

function getAllBlogs()
{   
    $sql = "SELECT * FROM blog ORDER BY id DESC ";
    $query = mysqli_query($conn, $sql);
    $result = mysqli_fetch_assoc($query);
            return $result;
}

<?php include("../Connections/db.php");?>
<?php include("functions.php");?>
    <?php 
            $result = getAllBlogs();
    foreach($result as $blogs) {
     echo "/".$blogs['id']."_".seoUrl($blogs['title']);
    }
    ?>

function getAllBlogs()
{   
    global $conn; // -> to get access to the variable, which is outside the method
    $sql = "SELECT * FROM blog ORDER BY id DESC ";
    $query = mysqli_query($conn, $sql);
    $result = mysqli_fetch_assoc($query);
            return $result;
}

blog.php

<?php
$servername = "localhost";
$username = "USERNAME";
$password = "*******";
$dbname = "dbname";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
?> 

function getAllBlogs()
{   
    $sql = "SELECT * FROM blog ORDER BY id DESC ";
    $query = mysqli_query($conn, $sql);
    $result = mysqli_fetch_assoc($query);
            return $result;
}

<?php include("../Connections/db.php");?>
<?php include("functions.php");?>
    <?php 
            $result = getAllBlogs();
    foreach($result as $blogs) {
     echo "/".$blogs['id']."_".seoUrl($blogs['title']);
    }
    ?>

function getAllBlogs()
{   
    global $conn; // -> to get access to the variable, which is outside the method
    $sql = "SELECT * FROM blog ORDER BY id DESC ";
    $query = mysqli_query($conn, $sql);
    $result = mysqli_fetch_assoc($query);
            return $result;
}

BLOG.php上的第33行是

foreach($result as $blogs) {

functions.php上的第17行和第18行是

$result1 = mysqli_query($conn, $sql);
        $result = mysqli_fetch_assoc($result1);

方法getAllBlogs（）没有用于返回值的变量

<?php

$result = getAllBlogs();

foreach($result as $blogs) 
{
    echo "/".$blogs['id']."_".seoUrl($blogs['title']);
} 

?>

---

您忘记将其赋给$result变量

 <?php
        $result=getAllBlogs();// assign to $result variable
        foreach($result as $blogs) {
       echo "/".$blogs['id']."_".seoUrl($blogs['title']);
     } ?>

---

首先在blog.php中包含functions.php文件。请使用下面的代码

<?php
require_once 'functions.php';
$result = getAllBlogs();

foreach($result as $blogs) 
{
    echo "/".$blogs['id']."_".seoUrl($blogs['title']);
} 

?>

您收到了什么信息？请在此共享。在blog.php中包含functions.php并检查。编写include_once（'functions.php'）；在blog.php之上，使用它可能是一个问题1。需要是

$result=getAllBlogs（）2。当您觉得某个答案为您提供了解决方案，包括您所问的所有其他问题时，您只获取了一行便笺：。谢谢。我编辑了我的问题以包含更多信息和错误。谢谢。我编辑了我的问题以包含更多信息和错误。谢谢。我编辑了我的问题以包含更多信息和错误。