如何获取不同键的和->；php数组中的值

我将以下字符串转换为json数组。我所要做的就是为

id\u number

组合具有相同值的键，将

amount

相加到每个键上，并在循环外打印结果值

$response = '{
               "nhif":[
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T20:18:50"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T19:59:14"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:07:34"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:04:27"
                  },
                  {
                     "id_number":"12345678",
                     "amount":"5",
                     "date":"2018-09-14T09:04:21"
                  }
               ]
            }';
$json_response = json_decode($response, true);

//Start NHIF
foreach ($json_response['nhif'] as $nhif) {
    echo ''.$nhif{"id_number"}.' '.$nhif{"amount"}.' '.$nhif{"date"}.'<br/>';
}
//END NHIF

任何解决方法？

您可以使用

id\u编号对
金额
值求和：

$sums = array_reduce($json_response['nhif'], function ($c, $i) { 
     $c[$i['id_number']] = (isset($c[$i['id_number']]) ? $c[$i['id_number']] : 0) + $i['amount']; 
     return $c; 
}, array());
print_r($sums);

输出：

AA112233    20
12345678    5


如果您使用的是PHP7，这个

isset($c[$i['id_number']]) ? $c[$i['id_number']] : 0

可以简化为

$c[$i['id_number']] ?? 0

您可以使用数组来解决此问题

$response = '{
               "nhif":[
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T20:18:50"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T19:59:14"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:07:34"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:04:27"
                  },
                  {
                     "id_number":"12345678",
                     "amount":"5",
                     "date":"2018-09-14T09:04:21"
                  }
               ]
            }';
$json_response = json_decode($response, true);

$results = array();  // will map the unique keys with it's sum
//Start NHIF
foreach ($json_response['nhif'] as $nhif) {
    if(!isset($results[$nhif['id_number']]))  // new key initialized
        $results[$nhif['id_number']] = $nhif['amount'];
    else
        $results[$nhif['id_number']] += $nhif['amount'];
}
//END NHIF

foreach($results as $key => $value) {
    echo $key .' '.$value;  // printing the result
}

对数组排序[如果数据未排序，则不需要排序]
执行for循环和求和
请尝试使用此代码示例，根据问题解决技巧，还有许多其他方法可以解决此问题

$response = '{
               "nhif":[
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T20:18:50"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T19:59:14"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:07:34"
                  },
                  {
                     "id_number":"AA112233",
                     "amount":"5",
                     "date":"2018-09-14T09:04:27"
                  },
                  {
                     "id_number":"12345678",
                     "amount":"5",
                     "date":"2018-09-14T09:04:21"
                  }
               ]
            }';
$data = json_decode($response, true);
usort($data['nhif'], function($a, $b) {
    return $b['id_number'] <=> $a['id_number'];
});

//Start NHIF
$amount = 0;
$id_number = null;
foreach($data['nhif'] as $nhif) {
    if(($nhif['id_number'] != $id_number) && ($id_number != null)){
        echo $id_number. "\t". $amount . "<br />";
        $id_number = $nhif['id_number'];
        $amount = $nhif['amount'];
    }
    else{
        $id_number = $nhif['id_number'];
        $amount = $amount + $nhif['amount'];
    }
    // echo ''.$nhif{"id_number"}.' '.$nhif{"amount"}.' '.$nhif{"date"}.'<br />';
}
echo $id_number. "\t". $amount . "<br />";
//END NHIF

$response={
“nhif”：[
{
“id_编号”：“AA112233”，
“金额”：“5”，
“日期”：“2018-09-14T20:18:50”
},
{
“id_编号”：“AA112233”，
“金额”：“5”，
“日期”：“2018-09-14T19:59:14”
},
{
“id_编号”：“AA112233”，
“金额”：“5”，
“日期”：“2018-09-14T09:07:34”
},
{
“id_编号”：“AA112233”，
“金额”：“5”，
“日期”：“2018-09-14T09:04:27”
},
{
“身份证号码”：“12345678”，
“金额”：“5”，
“日期”：“2018-09-14T09:04:21”
}
]
}';
$data=json_decode（$response，true）；
usort（$data['nhif']，函数（$a，$b）{
返回$b['id_number']$a['id_number']；
});
//启动NHIF
$amount=0；
$id_number=null；
foreach（$data['nhif']作为$nhif）{
if（$nhif['id\u number']！=$id\u number）&（$id\u number！=null））{
回显$id_编号。“\t”。$amount。“
”；
$id_number=$nhif['id_number']；
$amount=$nhif['amount']；
}
否则{
$id_number=$nhif['id_number']；
$amount=$amount+$nhif['amount']；
}
//回显'.$nhif{“id_number”}.'.$nhif{“amount”}.'.$nhif{“date”}.
'；
}
回显$id\u号码。“\t”$数量“
”；
//结束NHIF
您可以创建一个新数组，例如
$r
，并检查
$nhif['id\u number']
的键是否已经存在

如果是，则使用
+=
为
$nhif['amount']
添加值。如果没有，请使用
=

此示例使用
？：
运算符：

$r = [];
foreach ($json_response['nhif'] as $nhif) {
    isset($r[$nhif['id_number']]) ? $r[$nhif['id_number']] += $nhif['amount'] : $r[$nhif['id_number']] = $nhif['amount'];
}

我认为这个答案可能会有帮助[PHP JSON数组-按相同值分组]（）。基本上，您需要重新构造JSON数组，使其按相同的id_编号“分组”。所以，一旦结构正确，您只需要迭代它并执行求和逻辑。我为PHP5.xy编辑了它。在我看来，您的描述并没有说明太多。也许您需要对代码进行注释，以便更好地解释“数组”在何时何地排序有什么区别？如果数组未排序，则不需要排序。数组是否排序无关紧要。代码以相同的方式循环所有项。排序只需要时间，没有区别
$r = [];
foreach ($json_response['nhif'] as $nhif) {
    isset($r[$nhif['id_number']]) ? $r[$nhif['id_number']] += $nhif['amount'] : $r[$nhif['id_number']] = $nhif['amount'];
}