Php 在列表中查找下一个缺少的日期

我有一个预定日期的列表，存储在这样一个表中

1/1/2020
1/2/2020
1/3/2020
1/4/2020
1/6/2020
1/7/200
1/9/2020

我正试图找到第一个错过的日期，以便获得下一次的预订。我有以下代码

$this->inventory->addSelect(['next_available' => InventoryBookingItem::query()
    ->selectRaw('CASE WHEN date IS NOT NULL THEN DATE_ADD(`date`, INTERVAL 1 DAY) END')
    ->whereColumn('inventory_id', 'inventories.id')
    ->orderBy('date', 'desc')
    ->limit(1)
]);

---

<>这给了我<代码> 1/10/2020 <代码>，但我也需要考虑表中的空缺。如何从查询中实现这一点？

你可以考虑以下例子：

// create period for which you want to check for available dates
$period = new DatePeriod(
  new DateTime(),
  new DateInterval('P1D'),
  new DateTime('+1 month')
);
// your booked dates
$bookedDates = [
  '2020-07-16',
  '2020-07-17',
  '2020-07-19',
  '2020-07-21',
  '2020-07-26',
  '2020-08-01',
];

$dates = array_map(static function (DateTime $date) {
  return $date->format('Y-m-d');
}, iterator_to_array($period));

return array_diff($dates, $bookedDates); // it will return all available dates

---

你可以考虑下面的例子：

// create period for which you want to check for available dates
$period = new DatePeriod(
  new DateTime(),
  new DateInterval('P1D'),
  new DateTime('+1 month')
);
// your booked dates
$bookedDates = [
  '2020-07-16',
  '2020-07-17',
  '2020-07-19',
  '2020-07-21',
  '2020-07-26',
  '2020-08-01',
];

$dates = array_map(static function (DateTime $date) {
  return $date->format('Y-m-d');
}, iterator_to_array($period));

return array_diff($dates, $bookedDates); // it will return all available dates