如何在php类中使用另一个文件
我有两个文件dbconnect.php和config.php dbconnect.php如何在php类中使用另一个文件,php,sql,database,Php,Sql,Database,我有两个文件dbconnect.php和config.php dbconnect.php <?php class connect{ public function __construct(){ $config = require_once __DIR__ . 'config.php'; } private $dbhost = $config['host']; private $dbuser = $config['username'];
<?php
class connect{
public function __construct(){
$config = require_once __DIR__ . 'config.php';
}
private $dbhost = $config['host'];
private $dbuser = $config['username'];
private $dbpass = $config['pass'];
private $dbname = $config['dbname'];
public function startConn(){
$this->DBcon = null;
try{
$this->DBcon = new PDO("mysql:host=".$this->dbhost.";dbname=".$this->dbname, $this->dbuser, $this->dbpass);
}catch(Exception $e){
echo "error connecting:";
}
return $this->DBcon;
}
}
config.php
<?php
/**
* Contains all configurations
*
*/
return [
'dbname' => 'user',
'pass' => '@user.intern1',
'username' => 'user1',
'host' => 'localhost',
];
?>
在我的dbconnect.php文件中
如何将config.php中的变量包含到connect类中
如果我按照上面的方法做
它对我大喊大叫,给了我致命的错误:
“解析错误:语法错误,第8行C:\xampp\htdocs\hngfun\profile\adeojoemmanuel\php handler\dbconfig.php中意外的'$config'(T_变量)”无法为声明的属性(如private$dbhost
分配依赖于运行时数据的值,例如$config['host'”代码>
引述:
该声明可能包含一个初始化,但该初始化必须是一个常量值——也就是说,它必须能够在编译时进行计算,并且必须不依赖于运行时信息才能进行计算
在解决方案中,在构造函数中指定值:
class connect{
public function __construct(){
$config = require_once __DIR__ . 'config.php';
private $this->dbhost = $config['host'];
private $this->dbuser = $config['username'];
private $this->dbpass = $config['pass'];
private $this->dbname = $config['dbname'];
}
private $dbhost;
private $dbuser;
private $dbpass;
private $dbname;
public function startConn(){
$this->DBcon = null;
try{
$this->DBcon = new PDO("mysql:host=".$this->dbhost.";dbname=".$this->dbname, $this->dbuser, $this->dbpass);
}catch(Exception $e){
echo "error connecting:";
}
return $this->DBcon;
}
}
private $dbhost;
private $dbuser;
private $dbpass;
private $dbname;
public function __construct(){
$config = require_once __DIR__ . 'config.php';
$this->dbhost = $config['host'];
$this->dbuser = $config['username'];
$this->dbpass = $config['pass'];
$this->dbname = $config['dbname'];
}
您需要在构造函数内部设置:
class connect{
public function __construct(){
$config = require_once __DIR__ . 'config.php';
private $this->dbhost = $config['host'];
private $this->dbuser = $config['username'];
private $this->dbpass = $config['pass'];
private $this->dbname = $config['dbname'];
}
private $dbhost;
private $dbuser;
private $dbpass;
private $dbname;
public function startConn(){
$this->DBcon = null;
try{
$this->DBcon = new PDO("mysql:host=".$this->dbhost.";dbname=".$this->dbname, $this->dbuser, $this->dbpass);
}catch(Exception $e){
echo "error connecting:";
}
return $this->DBcon;
}
}
private $dbhost;
private $dbuser;
private $dbpass;
private $dbname;
public function __construct(){
$config = require_once __DIR__ . 'config.php';
$this->dbhost = $config['host'];
$this->dbuser = $config['username'];
$this->dbpass = $config['pass'];
$this->dbname = $config['dbname'];
}
我在猜。但我可以清楚地看到,您正在将$config设置为构造函数中的局部变量。这意味着一旦您离开构造函数,它就不可用
<?php
class connect{
public function __construct(){
$config = require_once __DIR__ . 'config.php';
$this->dbhost = $config['host'];
$this->dbuser = $config['username'];
$this->dbpass = $config['pass'];
$this->dbname = $config['dbname'];
}
private $dbhost ;
private $dbuser ;
private $dbpass ;
private $dbname ;
public function startConn(){
$this->DBcon = null;
try{
$this->DBcon = new PDO("mysql:host=".$this->dbhost.";dbname=".$this->dbname, $this->dbuser, $this->dbpass);
}catch(Exception $e){
echo "error connecting:";
}
return $this->DBcon;
}
}
第一个问题是,您不能仅从config.php文件返回任何内容。只能在函数内部返回结果。实现这一点的一种方法是将数组声明为全局变量,然后在需要该配置数组的所有其他php文件中使用它
<?php
/**
* Contains all configurations
*
*/
$dbconfig = array(
'dbname' => 'user',
'pass' => '@user.intern1',
'username' => 'user1',
'host' => 'localhost',
);
?>
<?php
require_once __DIR__ . 'config.php';
class connect{
public function __construct(){
}
private $dbhost = $dbconfig['host'];
private $dbuser = $dbconfig['username'];
private $dbpass = $dbconfig['pass'];
private $dbname = $dbconfig['dbname'];
public function startConn(){
$this->DBcon = null;
try{
$this->DBcon = new PDO("mysql:host=".$this->dbhost.";dbname=".$this->dbname, $this->dbuser, $this->dbpass);
}catch(Exception $e){
echo "error connecting:";
}
return $this->DBcon;
}
}
?>
最重要的是没有显示dbconfig.php的代码
声明的属性,如private$dbhost
不能分配依赖于运行时数据的值,如$config['host']
文件dbconfig.php
在哪里?我也这么认为。事实证明,您可以从require返回全局范围。不建议使用这种方法,但您可以这样做。include/require确实允许可以分配的返回,如中所述,并且不限于“全局”范围<代码>可以在包含的文件中执行return语句,以终止该文件中的处理并返回到调用它的脚本。此外,还可以从包含的文件中返回值。您可以像对待普通函数一样接受include调用的值代码>。。。事实上,Laravel在其配置文件中使用了这种方法,这对我来说也是一个学习新东西的好夜晚。谢谢分享:)