Php 删除Json格式上的字符串标题

Php 删除Json格式上的字符串标题,php,json,Php,Json,我做json编码,pfb我的代码 $encoded = json_encode($arr); var_dump($encoded); 结果如下所示 string(16007) "[{"NO":0,"GPSSTATE":"Valid Location","GPS":1,"TIME":1464666561,"USERNAME":"mostniaga","TIME_FORMAT":"31-May-2016 10:49:21","LICENSE":"B 2291 SFS","TERMINAL":"35

我做json编码,pfb我的代码

$encoded = json_encode($arr);
var_dump($encoded);
结果如下所示

string(16007) "[{"NO":0,"GPSSTATE":"Valid Location","GPS":1,"TIME":1464666561,"USERNAME":"mostniaga","TIME_FORMAT":"31-May-2016 10:49:21","LICENSE":"B 2291 SFS","TERMINAL":"358899052470419","OWNERTELP":" ","OWNERNAME":" ","TYPE":"IDTRACK","LONGITUDE":106.8083,"LATITUDE":-6.267059,"ADDRESS":"Pangeran Antasari-JAKARTA SELATAN (KOTA),DKI JAKARTA","SPEED":0,"DIRECTION":116,"MILEAGE":14055655,"ALARMSTATE":0,"CARSTATE":0,"ICONID":"0","GSM":"082212133958","STATUS":"Stop And Parking","STATUS_ENGINE":"ENGINE OFF","EXP_DATE":"Sep 7 2016 12:00:00:000AM","STATUS_EXP":"active","VEHICLE_STATE":" ","VEHICLE_TYPE":"Minibus"},
{"NO":1,"GPSSTATE":"Valid Location","GPS":1,"TIME":1464666653,"USERNAME":"mostniaga","TIME_FORMAT":"31-May-2016 10:50:53","LICENSE":"F 1540 KN","TERMINAL":"358899052465716","OWNERTELP":" ","OWNERNAME":" ","TYPE":"IDTRACK","LONGITUDE":106.8626,"LATITUDE":-6.480568,"ADDRESS":"Jagorawi-BOGOR,JAWA BARAT","SPEED":0,"DIRECTION":357,"MILEAGE":16698669,"ALARMSTATE":0,"CARSTATE":0,"ICONID":"0","GSM":"082212133959","STATUS":"Stop And Parking","STATUS_ENGINE":"ENGINE OFF","EXP_DATE":"Sep 7 2016 12:00:00:000AM","STATUS_EXP":"active","VEHICLE_STATE":" ","VEHICLE_TYPE":"Minibus"}]"
我想删除下面的这个字符串标题,怎么做

string(16007) "

如果您只是想输出json字符串,您可能只需要使用
echo$encoded
,例如,如果您有一个ajax调用,您可以将答案回显出来


然而,有一个经常被忽略的PHP命令,它将删除var_dump中的所有杂乱内容,并使其可复制,非常适合数组等,这就是
var_导出($encoded)
如果您只想输出json字符串,您可能只需要使用
echo$encoded
,例如,如果您有一个ajax调用,你可以呼应答案


然而,有一个PHP命令经常被忽略,它将删除var_dump中的所有杂乱内容,并使其可复制,非常适合数组等,这就是
var_导出($encoded)

首先
json_encode
没有TRUE作为参数。您可以使用正则表达式或json_decode unset和json_encode。然后不要使用
var_dump
,只需使用
echo
@FrayneKonok我已经删除了true,但字符串仍然存在,您能给我一个用于json_decode的url或示例吗unset@RodrigoDuterte感谢您的
json\u encode
必须返回字符串,要查看字符串,只需
echo
it,要查看类型,请使用
var\u dump
。首先
json\u encode
没有TRUE作为参数。您可以使用正则表达式或json_decode unset和json_encode。然后不要使用
var_dump
,只需使用
echo
@FrayneKonok我已经删除了true,但字符串仍然存在,您能给我一个用于json_decode的url或示例吗unset@RodrigoDuterte感谢您的
json\u encode
必须返回字符串,要查看字符串,只需
echo
it,要查看类型,请使用
var\u dump