PHP：我想计算文本文件中特定数量单词的出现次数

…（等等）

我想要这样：

if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 1 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.
if occurance are 0 times.
world occurance are 0 times.

---

如果您将整个单词列表放入一个数组中，您可以使用

if occurance are 47 times.
world occurance are 7 times.

有关更多信息，请参阅（或在一行中阅读）。然后，

$counts

将类似于

$counts = array_count_values($count_array)

然后，您可以循环查看该列表，检查该单词是否在您的单词列表中，并像

Array
(
    [if] => 47
    [world] => 7
    [otherword] => 17
)

试试这个：

$count_array = array("if", "world"); //words to search for and count

$word_counts = array();
//initialize the array like [word] => 0
foreach($count_array as $w) {
    $word_counts[$w] = 0;
}

$file = fopen('Data.txt', "r");
while(!feof($file))
{
    $line = trim(fgets($file));
    if ($line != "") {
        $OBJ = json_decode($line);
        $words = str_word_count($OBJ->user->text, 1); //return associative array of words

        foreach($words as $w) { //go through the list of returned words
            if (in_array($w, $count_array)) { //if this word is in our $count_array
                $word_counts[$w]++; //count it!
            }
        }
    }
}

foreach($word_counts as $word => $count) {
    echo '<b>' . $word . ' occurance are ' . $count . " times.</b><br />";
}

结果:

asd lol rotflol if
world rotflol world
bubu hehe gnigni if if
if hehe if world

---

file\u get\u content（）

是一次性读取整个文件的更好选择吗？如果您将整个单词列表放入一个数组，您只需使用

array\u count\u值（$count\u array）

（有关更多信息，请参阅）我不明白你为什么在文本文件中使用

json\u decode

：-/你能提供一个

Data.txt

所包含内容的示例吗？没错！谢谢，先生。非常感谢。

foreach($count_array as $word) {
    echo $word.'</b> occurrence is '.intval($counts[$word]).' times.<br>';
}

$count_array = array("if", "world"); //words to search for and count

$word_counts = array();
//initialize the array like [word] => 0
foreach($count_array as $w) {
    $word_counts[$w] = 0;
}

$file = fopen('Data.txt', "r");
while(!feof($file))
{
    $line = trim(fgets($file));
    if ($line != "") {
        $OBJ = json_decode($line);
        $words = str_word_count($OBJ->user->text, 1); //return associative array of words

        foreach($words as $w) { //go through the list of returned words
            if (in_array($w, $count_array)) { //if this word is in our $count_array
                $word_counts[$w]++; //count it!
            }
        }
    }
}

foreach($word_counts as $word => $count) {
    echo '<b>' . $word . ' occurance are ' . $count . " times.</b><br />";
}

<?php

$count_array = ["if" => 0,"world" => 0];

$file = fopen('Data.txt', "r");

while(!feof($file))
{
    $line = trim(fgets($file));

    $words = explode(" ", $line);

    foreach($words as $word) {
        if (array_key_exists($word, $count_array)) {
            $count_array[$word]++;
        }
    }
}

foreach ($count_array as $word => $number) {
    echo $word . " occurred " . $number . " times" . PHP_EOL;
}

asd lol rotflol if
world rotflol world
bubu hehe gnigni if if
if hehe if world

$ php script.php
if occurred 5 times
world occurred 3 times