从ajax请求转换php中的数组

我从ajax请求中得到了很多数组，我在php中得到了所有数组。我所做的是将它们组合在一起，得到了上面的结果。我的问题是，我无法单独获得返回的所有值。如何将上面的数组转换为如下所示。因此，我可以使用关键示例获得每个值

Array
(
    [0] => Array
        (
            [floor 1st Floor] => Reinforced Concrete
        )

    [1] => Array
        (
            [floor 2nd Floor] => Plain Cement
        )

    [2] => Array
        (
            [floor 3rd Floor] => Plain Cement
        )

    [3] => Array
        (
            [floor 3rd Floor] => Marble
        )

    [4] => Array
        (
            [floor 4th Floor] => Marble
        )

    [5] => Array
        (
            [floor 4th Floor] => Wood
        )

    [6] => Array
        (
            [floor 3rd Floor] => eqweqw
        )

    [7] => Array
        (
            [wall 1st Floor] => Reinforced Concrete
        )

    [8] => Array
        (
            [wall 2nd Floor] => Plain Cement
        )

    [9] => Array
        (
            [wall 4th Floor] => Plain Cement
        )

    [10] => Array
        (
            [wall 3rd Floor] => CHB
        )

    [11] => Array
        (
            [wall 3rd Floor] => ewqewqq
        )

    [12] => Array
        (
            [roof] => Tiles
        )

    [13] => Array
        (
            [roof] => qweqe
        )

)

或者，如果可能的话，如何像下面这样从第一个数组中获取所有值

echo$value['wall 3rd Floor']

foreach ($material as $value) {
echo $value['wall 3rd Floor'];
}

我尝试了几种类似的方法，但没有得到理想的结果

Array
(
    [0] => Array
        (
            [floor 1st Floor] => Reinforced Concrete
            [floor 2nd Floor] => Plain Cement
            [floor 3rd Floor] => Plain Cement
            [floor 3rd Floor] => Marble
            [floor 4th Floor] => Marble
            [floor 4th Floor] => Wood
            [floor 3rd Floor] => eqweqw
            [wall 1st Floor] => Reinforced Concrete
            [wall 2nd Floor] => Plain Cement
            [wall 4th Floor] => Plain Cement
            [wall 3rd Floor] => CHB
            [wall 3rd Floor] => ewqewqq
            [roof] => Tiles
            [roof] => qweqe
        )

)

for（$i=0；$i”；
}
下一个（$数组）；
}
您只需将foreach（）加倍即可。

它：

for ($i = 0; $i <  count($array); $i++) {
    $key=key($array);
    $val=$array[$key];
    if ($val<> ' ') {
       echo $key ." = ".  $val ." <br> ";
       }
     next($array);
    }

然后，您可以随意访问它：

$new = array();
foreach($data as $item) {
    foreach($item as $key => $value) {
        $new[$key] = $value;
    }
}

---

或者，如果您想要更短的回路，可以通过利用和：

解释

• key（）

  获取

  $item

• current（）

  获取

  $item

---

您是否尝试过类似的方法： foreach（数组为$key=>$value） { echo$key.“=”$value.“
”；

---

}

先生，我可以使用数组

$data=[['floor 1st floor'=>'钢筋混凝土']，['floor 2nd floor'=>'素水泥']，['floor 3rd floor'=>'素水泥']，]获取值问题是当数组是第一个数组时示例
数组（[0]=>数组（[floor 1st floor]=>钢筋混凝土）[1]=>数组（[floor 2nd floor]=>素水泥））
@Pekka这就是我从中获取的。您提供的第一个数组。你必须按你想要的方式创建一个新数组。让我再试一次，先生，也许我弄错了，
$new['wall 3rd Floor']
这将响应值
CHB
和
ewqewqq
对吗？让我再检查一遍，先生等等，你有相同的钥匙。这将导致一个问题，因为值将被原始数组中最后一个类型的值覆盖。我看到了被覆盖的数据如何避免被覆盖？
echo $new['wall 3rd Floor'];

$new = array();
foreach($data as $item) {
    $new[key($item)] = current($item);
}