Php mysql查询-仅从另一个表中选择其中id=id,并且该表中的字段=值
我的标题可能无法解释我要找的是什么,这是我目前对某商店推出产品的查询:Php mysql查询-仅从另一个表中选择其中id=id,并且该表中的字段=值,php,mysql,Php,Mysql,我的标题可能无法解释我要找的是什么,这是我目前对某商店推出产品的查询: mysql_query("SELECT * FROM Items WHERE ((Items.menu_id='$menu_id' AND Items.status='1') $colour_sql) $order_sql LIMIT $lim_from,$limit_per_page"); 上面写着
mysql_query("SELECT * FROM Items
WHERE ((Items.menu_id='$menu_id' AND Items.status='1')
$colour_sql)
$order_sql
LIMIT $lim_from,$limit_per_page");
上面写着$COLOR\u sql的那部分我想说:
AND (Items.id=colour.product_id AND colour.colour='pink')
所以它只显示粉红色的产品,颜色在单独的表格中。我一直在寻找答案,但我似乎找不到一个能解释我的情况的答案,可能是因为我不知道自己在寻找什么,谢谢你的帮助。也许是内心的加入
[...]
FROM Items
INNER JOIN colour
ON colour.id = Items.colour_id
WHERE [blablabla]
AND colour.colour = 'pink'
也许是内部连接
[...]
FROM Items
INNER JOIN colour
ON colour.id = Items.colour_id
WHERE [blablabla]
AND colour.colour = 'pink'
如果要使用table
color
进行连接,则需要执行连接或子选择
加入
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
INNER JOIN colour c ON (c.product_id = i.id)
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND c.colour = 'pink'
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND i.id IN (SELECT c.product_id FROM colour c WHERE c.colour = 'pink')
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
子选择
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
INNER JOIN colour c ON (c.product_id = i.id)
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND c.colour = 'pink'
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND i.id IN (SELECT c.product_id FROM colour c WHERE c.colour = 'pink')
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
如果要使用table
color
进行连接,则需要执行连接或子选择
加入
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
INNER JOIN colour c ON (c.product_id = i.id)
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND c.colour = 'pink'
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND i.id IN (SELECT c.product_id FROM colour c WHERE c.colour = 'pink')
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
子选择
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
INNER JOIN colour c ON (c.product_id = i.id)
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND c.colour = 'pink'
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
$menu_id = mysql_real_escape_string($menu_id);
mysql_query = "SELECT i.*
FROM items i
WHERE i.menu_id = '$menu_id'
AND i.status = '1'
AND i.id IN (SELECT c.product_id FROM colour c WHERE c.colour = 'pink')
ORDER BY .....
LIMIT {intval($limit_per_page)} OFFSET {intval($lim_from)} ";
您需要将颜色表添加到查询中:
FROM Items,colour
或
但我注意到您的颜色表中有产品标识。为什么不在添加颜色id的项目表中执行相反的操作。您需要将颜色表添加到查询中:
FROM Items,colour
或
但我注意到您的颜色表中有产品标识。为什么不在项目表中做相反的操作,添加颜色id。产品可以有多种颜色,所以我不能这样做,如果我理解正确,这只是一个观察:)产品可以有多种颜色,所以我不能这样做,如果我理解正确,这只是一个观察:)