Php 将sql表导入html时获取0结果
我刚开始使用mysql和php 我试图在表中显示mysql数据库。代码似乎正在运行,但它给出了0个结果。我在mysql表中有2行Php 将sql表导入html时获取0结果,php,html,mysqli,html-table,Php,Html,Mysqli,Html Table,我刚开始使用mysql和php 我试图在表中显示mysql数据库。代码似乎正在运行,但它给出了0个结果。我在mysql表中有2行 <!DOCTYPE html> <html lang="en"> <head> <title>Tronios Exportzendingen</title> <meta charset="utf-8"> <meta name="viewport" content="width=d
<!DOCTYPE html>
<html lang="en">
<head>
<title>Tronios Exportzendingen</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<link rel="stylesheet" type="text/css" href="styles2.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.0/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>
<?php
$servername = "localhost";
$username = "rubinjo13";
$dbname = "project1";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "ExportID, Debiteur, Deb_Name, Tot_Pallets, Tot_Weight, PBS FROM export";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>ID</th><th>Debiteur</th><th>Naam</th><th>Aantal Pallets</th><th>Totaal Gewicht</th><th>PB Nummers</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["ExportID"]. "</td><td>" . $row["Debiteur"]. " " . $row["Deb_Name"]. "</td></tr>"
. $row["Tot_Pallets"]. "</td><td>" . $row["Tot_Weight"]. "</td><td>" . $row["PBS"]. "</td><td>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
</body>
</html>
特罗尼奥斯出口公司
希望有人能帮助我:)您错过了查询中的选择:
$sql = "SELECT ExportID, Debiteur, Deb_Name, Tot_Pallets, Tot_Weight, PBS FROM export";
$sql=“出口标识、借方、借方名称、托托托盘、托托重量、出口PBS”??你怎么错过了选择??