Php 将JSON字符串转换为数组

我有这个JSON字符串

{"ticker":{"high":736.45099,"low":681,"avg":708.725495,"vol":13038780.63684,"vol_cur":18382.55965,"last":726,"buy":726,"sell":724.5,"updated":1388242741,"server_time":1388242743}}

在执行

json\u decode（）

之后，如何获取“last”参数

<?php
$json='{"ticker":{"high":736.45099,"low":681,"avg":708.725495,"vol":13038780.63684,"vol_cur":18382.55965,"last":726,"buy":726,"sell":724.5,"updated":1388242741,"server_time":1388242743}}';
$json_arr=json_decode($json,true);
echo $json_arr['ticker']['server_time'];//"prints" 1388242743 which is the last param "server time"

你喜欢这样做吗

<?php
$json='{"ticker":{"high":736.45099,"low":681,"avg":708.725495,"vol":13038780.63684,"vol_cur":18382.55965,"last":726,"buy":726,"sell":724.5,"updated":1388242741,"server_time":1388242743}}';
$json_arr=json_decode($json,true);
echo $json_arr['ticker']['server_time'];//"prints" 1388242743 which is the last param "server time"

使用json\u decode和参数json string和TRUE。如果为TRUE，返回的对象将转换为关联数组

<?php
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';     
var_dump(json_decode($json, true));    
?>



使用参数json字符串和TRUE的json\u decode。如果为TRUE，返回的对象将转换为关联数组

<?php
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';     
var_dump(json_decode($json, true));    
?>



$jsonArray=json_decode（“…”，true）echo$jsonArray['ticker']['last']
$jsonArray=json_decode（'…'，true）echo$jsonArray['ticker']['last']
实际上，op询问如何获取名为
“last”
的参数。除此之外，这个答案是正确的。我也以类似的方式思考，因此+1.：）实际上，op要求获取名为
“last”
的参数。除此之外，这个答案是正确的。我也以类似的方式思考，因此+1.：）