当数据库中已有数据时，PHP无法从数据库中获取用户数据

这是密码！当数据库中已有数据时，PHP无法从数据库中获取用户数据！帮帮我，我卡住了。当我在login.php中输入详细信息时，它会将我重定向到login.php？invalid=1，并显示错误信息错误或会话已过期！尽管信息是一样的

<?php 
    session_start();
    include_once("include\config.php");
    $login = $_POST["textfield1"];
    $pwd = $_POST["textfield2"];
    $recordset = mysql_query("select * from users");
    while($record = mysql_fetch_array($recordset)){
    if($login == $record["ulogin"] && $pwd == $record["upassword"]) {
        $_SESSION["ulogin"] = $record["ulogin"];
        $_SESSION["uid"] = $record["uid"];  
        if($record["utype"] == 1){
                $_SESSION["utype"] = $record["utype"];
                header("Location:admin.php?uid=".$record["uid"]);
                exit;
        }else{
                header("Location:home.php");
                exit;
            }
        }
    }
    header("Location:login.php?invalid=1");
?>

我已经改变了 发件人：

致：

及

发件人：

><?php 
session_start();

$recordset = mysql_query("select * from users");

致：

请用此代码替换您的代码，然后重试。希望这对你有帮助

<?php 
session_start();
include_once("include/config.php");
$login = $_POST["textfield1"];
$pwd = $_POST["textfield2"];
$recordset = mysql_query("select * from users WHERE username = "'.$login.'" AND password = "'.$pwd.'"");
while($record = mysql_fetch_array($recordset)){
if($login == $record["ulogin"] && $pwd == $record["upassword"]) {

$_SESSION["ulogin"] = $record["ulogin"];
$_SESSION["uid"] = $record["uid"];  
        if($record["utype"] == 1){
        $_SESSION["utype"] = $record["utype"];
        header("Location:admin.php?uid=".$record["uid"]);
        exit;
        }else{
    header("Location:home.php");
    exit;
    }
 }
} 

       header("Location:login.php?invalid=1");  
   ?>

---

Change

include_once（“include\config.php”）

到

包含一次（“include/config.php”）
包括您的
config.php
文件，如下所示：

include_once("include/config.php");

include_once("include\config.php");

不可能是这样的：

include_once("include/config.php");

include_once("include\config.php");

使用下面的查询

select * from users WHERE username = "'.$login.'" AND password = "'.$pwd.'"

然后，您不需要一次又一次地循环所有记录

请确保数据库表有记录。
包含数据库配置文件时出现问题。

Repalce

include_once("include\config.php");

与

include_once("include/config.php");

您不应该使用mysql库-它已被弃用。请转换为mysqli_uu或PDO
include_once（“include\config.php”）
应该是
include_once（“include/config.php”）

查询
select*from users
可能返回大量记录。更好的查询应该是：

mysql_query（“select*from users where ulogin='”。mysql_real_escape（$login）。“”和“upassword='”。$pwd.”）

这应该返回一行或不返回任何行。保存扫描整个用户表，解释您所做的更改。是的，您应该解释您所做的更改。我已经做了。很抱歉我的错误，感谢您的建议非常感谢！这很有帮助：）感谢您的回答！如果我的回答对您有帮助，那么请正确回答，这样它就会正确对其他用户很有帮助，因为您似乎以纯文本形式保存密码。请不要这样做。另外请注意，
mysql\uu
函数已被弃用，不应再使用。请改用PDO或MySQLi。
 <?php
    session_start();
    // http://stackoverflow.com/questions/15408037/php-not-getting-user-data-from-database-when-data-is-already-in-database
    include_once("include/config.php");
    $login = $_POST["textfield1"];
    $pwd = $_POST["textfield2"];
    $recordset = mysql_query("select * from users WHERE ulogin = "'.$login.'" AND upassword = "'.$pwd.'"" ");
    $num_row_user =mysql_num_rows($recordset);
    if($num_row_user>0)
    {
       while($record = mysql_fetch_array($recordset))
       {
         if($record["utype"] == 1) 
         {
            $_SESSION["ulogin"] = $record["ulogin"];
            $_SESSION["uid"] = $record["uid"];
            $_SESSION["utype"] = $record["utype"];
            header("Location:admin.php?uid=".$record["uid"]);
            exit;
         }
         else
         {
            header("Location:home.php");
            exit;
         }
       }
    }
    else
    {
       if (mysql_errno()) 
       { 
          header("Location:login.php?invalid=1&message=QueryError");
       }
       else
       {
          header("Location:login.php?invalid=1&message=invalid username and password");
       } 

    }

include_once("include/config.php");

 <?php
    session_start();
    // http://stackoverflow.com/questions/15408037/php-not-getting-user-data-from-database-when-data-is-already-in-database
    include_once("include/config.php");
    $login = $_POST["textfield1"];
    $pwd = $_POST["textfield2"];
    $recordset = mysql_query("select * from users WHERE ulogin = "'.$login.'" AND upassword = "'.$pwd.'"" ");
    $num_row_user =mysql_num_rows($recordset);
    if($num_row_user>0)
    {
       while($record = mysql_fetch_array($recordset))
       {
         if($record["utype"] == 1) 
         {
            $_SESSION["ulogin"] = $record["ulogin"];
            $_SESSION["uid"] = $record["uid"];
            $_SESSION["utype"] = $record["utype"];
            header("Location:admin.php?uid=".$record["uid"]);
            exit;
         }
         else
         {
            header("Location:home.php");
            exit;
         }
       }
    }
    else
    {
       if (mysql_errno()) 
       { 
          header("Location:login.php?invalid=1&message=QueryError");
       }
       else
       {
          header("Location:login.php?invalid=1&message=invalid username and password");
       } 

    }