Php MySQL在表中找不到特定行
我刚进入PHP,我想做一个简单的数据查找脚本。这是我现在在index.php文件中使用的代码Php MySQL在表中找不到特定行,php,mysql,Php,Mysql,我刚进入PHP,我想做一个简单的数据查找脚本。这是我现在在index.php文件中使用的代码 <?php $mysqlHost = 'localhost'; $mysqlUser = 'root'; $mysqlPass = 'password'; $mysqlDatabase = 'core'; $conn = new mysqli($mysqlHost, $mysqlUser, $mysqlPass, $mysqlDatabase);
<?php
$mysqlHost = 'localhost';
$mysqlUser = 'root';
$mysqlPass = 'password';
$mysqlDatabase = 'core';
$conn = new mysqli($mysqlHost, $mysqlUser, $mysqlPass, $mysqlDatabase);
if ($conn -> connect_error)
die('Connection Failed: ' . $conn -> connect_error);
$sql = 'SELECT * FROM users WHERE name = SimonM34';
$result = $conn -> query($sql);
if ($result -> num_rows > 0) {
$row = $result -> fetch_assoc();
$rawJson -> name = $row['name'];
$rawJson -> rank = $row['rank'];
$rawJson -> subrank = $row['subrank'];
$rawJson -> balance = $row['balance'];
$json = json_encode($rawJson);
echo $json;
} else {
echo 'No users found!';
}
$conn -> close();
?>
这总是显示找不到用户,但如果我将语句更改为SELECT*FROM users,它将返回{name:SimonM34,rank:Guest,subrank:None,balance:500},这非常奇怪,我无法理解为什么会发生这种情况
谢谢问题出在您的查询中:
$sql = 'SELECT * FROM users WHERE name = SimonM34';
您正在比较不带引号的字符串值。将查询替换为以下内容:
$sql = 'SELECT * FROM users WHERE name = "SimonM34"';
我想这是唯一的问题。这不是重复的,因为我对所有表名都使用小写。太棒了,谢谢