Php setInterval，ajax请求

获取ajax请求的最佳方法是什么

我的每次调用javascript函数都会越来越快 我不知道为什么

代码如下：

$(function(){
getSuggestions();
});

function getSuggestions(){
    var url = $("#baseUrl").val() + '/placement/suggestions/x-fetch-suggestions';
    var data ={}
    var result = myAjaxJson(data,url); //gets json object via ajax

/* gets object 'sug' and put into #suggestions-list*/
    $('#suggestions-list').html(result.sug);

    var a = setInterval("getSuggestions()",5000);
}

---

每次调用getSuggestions时，都会启动新的setInterval。把它放在外面：

$(function(){
    var a = setInterval("getSuggestions()",5000);
});

代替

$(function(){
    getSuggestions();
});

---

并从getSuggestions方法中删除setInterval代码。

每次调用getSuggestions时，都会启动新的setInterval。把它放在外面：

$(function(){
    var a = setInterval("getSuggestions()",5000);
});

代替

$(function(){
    getSuggestions();
});

---

并从getSuggestions方法中删除setInterval代码。

这里有一种递归双循环

试试这个：

$(function(){
   var a = setInterval("getSuggestions()",5000);
});

function getSuggestions(){
    var url = $("#baseUrl").val() + '/placement/suggestions/x-fetch-suggestions';
    var data ={}
    var result = myAjaxJson(data,url); //gets json object via ajax

/* gets object 'sug' and put into #suggestions-list*/
    $('#suggestions-list').html(result.sug);


}

---

这里有一个递归的双循环

试试这个：

$(function(){
   var a = setInterval("getSuggestions()",5000);
});

function getSuggestions(){
    var url = $("#baseUrl").val() + '/placement/suggestions/x-fetch-suggestions';
    var data ={}
    var result = myAjaxJson(data,url); //gets json object via ajax

/* gets object 'sug' and put into #suggestions-list*/
    $('#suggestions-list').html(result.sug);


}

---

不要使用setInterval，使用setTimeout。setInterval每5秒调用一次函数，无论上一个Ajax请求是否完成。setTimeout将在上一个Ajax请求后等待5秒，以启动下一个Ajax请求：

$(function(){
getSuggestions();
});

function getSuggestions(){
    var url = $("#baseUrl").val() + '/placement/suggestions/x-fetch-suggestions';
    var data ={}
    var result = myAjaxJson(data,url); //gets json object via ajax

/* gets object 'sug' and put into #suggestions-list*/
    $('#suggestions-list').html(result.sug);

    var a = setTimeout("getSuggestions()",5000);
}

---

不要使用setInterval，使用setTimeout。setInterval每5秒调用一次函数，无论上一个Ajax请求是否完成。setTimeout将在上一个Ajax请求后等待5秒，以启动下一个Ajax请求：

$(function(){
getSuggestions();
});

function getSuggestions(){
    var url = $("#baseUrl").val() + '/placement/suggestions/x-fetch-suggestions';
    var data ={}
    var result = myAjaxJson(data,url); //gets json object via ajax

/* gets object 'sug' and put into #suggestions-list*/
    $('#suggestions-list').html(result.sug);

    var a = setTimeout("getSuggestions()",5000);
}

---

请添加

myAjaxJson

的实现，您应该等待英特尔ajax完成，然后启动

setInterval

setInterval

将重复调用该函数，不止一次：请添加

myAjaxJson

的实现。您应该等待英特尔ajax完成，然后启动

setInterval

setInterval

将重复调用该函数，而不仅仅是一次：