Php 提交表单时，我收到错误，但不确定原因

为什么我在提交此表单时收到回音声明“错误”

我从for register.php获得了这段代码

到昨天为止，它对我的用户运行良好，但似乎找不到原因

我想可能是我的config.php，但如果用户名已经在使用中，它会打印错误消息，因此看起来不是config.php。我给网站发了一条消息，说我是从那里得到代码的，他们帮不了我

<?php
// Include config file
require_once "config.php";

// Define variables and initialize with empty values
$username = $password = $confirm_password = "";
$username_err = $password_err = $confirm_password_err = "";

// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){

    // Validate username
    if(empty(trim($_POST["username"]))){
        $username_err = "Please enter a username.";
    } else{
        // Prepare a select statement
        $sql = "SELECT id FROM sign_in_account WHERE username = ?";

        if($stmt = mysqli_prepare($link, $sql)){
            // Bind variables to the prepared statement as parameters
            mysqli_stmt_bind_param($stmt, "s", $param_username);

            // Set parameters
            $param_username = trim($_POST["username"]);

            // Attempt to execute the prepared statement
            if(mysqli_stmt_execute($stmt)){
                /* store result */
                mysqli_stmt_store_result($stmt);

                if(mysqli_stmt_num_rows($stmt) == 1){
                    $username_err = "This username is already taken.";
                } else{
                    $username = trim($_POST["username"]);
                }
            } else{
                echo "Oops! Something went wrong. Please try again later.";
            }
        }

        // Close statement
        mysqli_stmt_close($stmt);
    }

    // Validate password
    if(empty(trim($_POST["password"]))){
        $password_err = "Please enter a password.";     
    } elseif(strlen(trim($_POST["password"])) < 6){
        $password_err = "Password must have atleast 6 characters.";
    } else{
        $password = trim($_POST["password"]);
    }

    // Validate confirm password
    if(empty(trim($_POST["confirm_password"]))){
        $confirm_password_err = "Please confirm password.";     
    } else{
        $confirm_password = trim($_POST["confirm_password"]);
        if(empty($password_err) && ($password != $confirm_password)){
            $confirm_password_err = "Password did not match.";
        }
    }

    // Check input errors before inserting in database
    if(empty($username_err) && empty($password_err) && empty($confirm_password_err)){

        // Prepare an insert statement
        $sql = "INSERT INTO sign_in_account (username, password) VALUES (?, ?)";

        if($stmt = mysqli_prepare($link, $sql)){
            // Bind variables to the prepared statement as parameters
            mysqli_stmt_bind_param($stmt, "ss", $param_username, $param_password);

            // Set parameters
            $param_username = $username;
            $param_password = password_hash($password, PASSWORD_DEFAULT); // Creates a password hash

            // Attempt to execute the prepared statement
            if(mysqli_stmt_execute($stmt)){
                // Redirect to login page
                header("location: login.php");
            } else{
                echo "Something went wrong. Please try again later. error: 1";//Error 1 = form submission
            }
        }

        // Close statement
        mysqli_stmt_close($stmt);
    }

    // Close connection
    mysqli_close($link);
}
?>

---

在成功提交结果时，输出应该转到my login.php页面，但打印我的echo语句“echo”时出错。请稍后再试。错误：1“；”

有关数据库连接的某些内容已断开

mysqli\u stmt\u execute（$stmt）

返回

false

。你对此做了任何更改吗？哪个“错误”声明？而不是说“错误：1”为什么不实际检查错误消息？@theblackips我已经两周没有更改服务器上的任何内容了。但它在两天前就开始工作了，因为我们在我的数据库中创建了新用户。然后我被告知它昨天不工作。@CodyO'Meara正如其他人所说的，请检查您的php错误日志。有关您的数据库连接的某些内容已断开

mysqli\u stmt\u execute（$stmt）

返回

false

。你对此做了任何更改吗？哪个“错误”声明？而不是说“错误：1”为什么不实际检查错误消息？@theblackips我已经两周没有更改服务器上的任何内容了。但它在两天前就开始工作了，因为我们在我的数据库中创建了新用户。然后我被告知它昨天不工作。@CodyO'Meara正如其他人所说，请检查您的php错误日志。