Php MySQL错误：第5行的“按时间戳顺序描述限制1”

我尝试在MRBS日历中运行Rowland Carson的脚本showcalendar.php几天。我在数据库中遇到了一些错误，但现在遇到了以下问题：

您的SQL语法有错误；查看与MySQL服务器版本对应的手册，以了解第5行“按时间戳排序desc limit 1”附近使用的正确语法

我使用MRBS 1.4.11、Apache/2.2.16 Debian、MySQL客户端版本：5.1.66。 我发现这个主题： 还查阅了一些信息并进行了研究 但没有进展。请你能帮我或给我一些正确方向的建议吗？ 非常感谢您的时间和精力：

$conn = mysql_connect($mysql_host, $mysql_user, $mysql_pass)

or die(mysql_error());

mysql_select_db("mrbs", $conn)  or die(mysql_error());



$get_entries = "select timestamp

from $bookings

order by timestamp desc

limit 1

"

;

$entries_result = mysql_query($get_entries) or die(mysql_error());

$data_row = mysql_fetch_object($entries_result);

$last_changed = $data_row->timestamp;



$get_rooms = "select *

from $rooms

order by id

"

;

$rooms_result = mysql_query($get_rooms) or die(mysql_error());

$n_rooms = mysql_num_rows($rooms_result);

$n_cols = $n_rooms + 1;



$booking_block = "<TABLE align=center BORDER=1 CELLPADDING=5>\n";

$booking_block .= "<tr><td colspan=".$n_cols.">";

$booking_block .= "Room bookings for week beginning ";

$booking_block .= $startingDateArray['mday']." ";

$booking_block .= $startingDateArray['month']." ";

$booking_block .= $startingDateArray['year']." ";

$booking_block .= "(Last change to any booking was made ";

$booking_block .= $last_changed;

$booking_block .= ")</td></tr>\n";

$booking_block .= "<tr><td align=right>".$startYear."</td>\n";



while ($rooms = mysql_fetch_array($rooms_result, MYSQL_ASSOC))

{

$booking_block .= "<td>";

$booking_block .= $rooms['room_name'];

$booking_block .= "</td>";

}

$booking_block .= "</tr>\n";



for ($day_number = 0; $day_number <= 6; $day_number++)

{

$booking_block .= "<tr>\n";

$booking_block .= "<td align=right valign=top>";

$endOfDay = $theTimestamp + ONE_DAY;

$theDateArray = getdate($theTimestamp);

if ($theDateArray['year'] != $startYear)

{

    $startYear = $theDateArray['year'];

    $booking_block .= $startYear."<br>";

}

$booking_block .= date("D d M", $theTimestamp)."</td>\n";



for ($room_number = 1; $room_number <= $n_rooms; $room_number++)

{

    $get_bookings = "select *

        from $bookings

        where start_time >= $theTimestamp

        and start_time <= $endOfDay

        and room_id = $room_number

        order by start_time

        "

        ;

    $bookings_result = mysql_query($get_bookings) or die(mysql_error());

    $booking_block .= "<td valign=top>";

    if (mysql_num_rows($bookings_result) > 0)

    {

        while ($booking_entry = mysql_fetch_array($bookings_result, MYSQL_ASSOC))

        {

            $booking_block .= date("H:i", $booking_entry['start_time']);

            $booking_block .= "-";

            $booking_block .= date("H:i", $booking_entry['end_time']);

            $booking_block .= " ";

            $booking_block .= $booking_entry['name'];

            $booking_block .= "<br>\n";

        }

    }

    else

    {

        $booking_block .= "<br>";

    }

    $booking_block .= "</td>";

}

$booking_block .= "</tr>\n";

$theTimestamp = $theTimestamp + ONE_DAY;

}



$booking_block .= "<tr><td colspan=".$n_cols." align=right>";

$booking_block .= "This web page rendered at ";

$booking_block .= sprintf("%02d:%02d:%02d",

                        $nowArray['hours'],

                        $nowArray['minutes'],

                        $nowArray['seconds']);

$booking_block .= " on ";

$booking_block .= $nowArray['mday']." ";

$booking_block .= $nowArray['month']." ";

$booking_block .= $nowArray['year']." ";



$booking_block .= "</table>\n";

---

MySQL的错误片段从错误发生后的查询点开始。既然你得到的是。。。在错误输出中，这意味着错误就在该点之前，这可能意味着$bookings未定义，您的查询如下

SELECT timestamp
FROM
ORDER BY timestamp DESC

---

请注意，缺少表名。echo$get\u条目将证实这一点。

我不想成为那个家伙，但你不应该使用mysql。一旦你解决了你的问题，你应该看到这个谢谢！我们将检查这些主题，希望很快就能了解。谢谢你的回答。不幸的是$bookings被定义了……接下来会是什么呢？那么它的价值是什么呢？如果它是一个无效的字段名，就像要做的事情一样，那么您必须引用整个值以使其成为合法的表名。值为$bookings=mrbs\u entry值为$bookings=mrbs\u entry mrbs\u entry=数据库中的表名