文件上传ajaxphp
我有一段javascript,它使用Ajax和PHP上传图像 我在几个html页面的头部使用javascript,我想知道是否有一种方法可以将这些页面的值传递到Upload.php文件,而不必为每个网页创建单独的Upload.php文件 javascript的第三部分:文件上传ajaxphp,php,javascript,mysql,html,ajax,Php,Javascript,Mysql,Html,Ajax,我有一段javascript,它使用Ajax和PHP上传图像 我在几个html页面的头部使用javascript,我想知道是否有一种方法可以将这些页面的值传递到Upload.php文件,而不必为每个网页创建单独的Upload.php文件 javascript的第三部分: <script type="text/javascript" > $(function(){ var btnUpload=$('#me'); var m
<script type="text/javascript" >
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php',
name: 'uploadfile',
$(函数(){
var btnUpload=$(“#me”);
变量mestatus=$(“#mestatus”);
var files=$(“#files”);
新AjaxUpload(btnUpload{
操作:'../UploadDoc/Upload.php',
名称:“上载文件”,
我想将值传递给Upload.php文件的以下部分:
<?php
/* Set the location to upload the file to */
$uploaddir = '../documents/userdocs/';
/* Set the name and file extension of the file being saved */
$file = $uploaddir ."HtmlPage1_".basename($_FILES['uploadfile']['name']);
$file_name= "HtmlPage1_".$_FILES['uploadfile']['name'];
在Javascript中
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php',
name: 'uploadfile',
params: {
pageKey: 'HtmlPage1_'
}
......ETC-CODE......................
或者你的javascript代码做什么
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php?pageKey=HtmlPage1_',
name: 'uploadfile',
......ETC-CODE......................
在您的PHP中:
<?php
/* Set the location to upload the file to */
$uploaddir = '../documents/userdocs/';
/* Set the name and file extension of the file being saved */
$file = $uploaddir .$_REQUEST['pageKey'].basename($_FILES['uploadfile']['name']);
$file_name= $_REQUEST['pageKey'].$_FILES['uploadfile']['name'];
......ETC-CODE......................
在Javascript中
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php',
name: 'uploadfile',
params: {
pageKey: 'HtmlPage1_'
}
......ETC-CODE......................
或者你的javascript代码做什么
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php?pageKey=HtmlPage1_',
name: 'uploadfile',
......ETC-CODE......................
在您的PHP中:
<?php
/* Set the location to upload the file to */
$uploaddir = '../documents/userdocs/';
/* Set the name and file extension of the file being saved */
$file = $uploaddir .$_REQUEST['pageKey'].basename($_FILES['uploadfile']['name']);
$file_name= $_REQUEST['pageKey'].$_FILES['uploadfile']['name'];
......ETC-CODE......................
感谢您的回复。不幸的是,尽管文件仍在上传,但参数值似乎没有到达PHP文件。文件以正常名称保存,减去预期的“HtmlPage1”前缀。知道为什么会这样吗?请告诉我发布更多代码是否有帮助。另一种方法是感谢您的回复不幸的是,尽管文件仍在上传中,但param值似乎没有到达PHP文件。文件保存时使用的是正常名称,减去预期的“HtmlPage1_”前缀。知道为什么会这样吗?请告诉我发布更多代码是否有帮助。另一种方法是这样做