Php 使用一个脚本而不是另一个脚本的注册函数

我在一个脚本上有一个注册函数，我已经将它复制到一个新的项目中，并更改了变量——表单输入、表/数据库名称等，而脚本不会做任何事情

Signup.php

<form class="form" action="register.php" method="POST" enctype="application/x-www-form-urlencoded">

    <input type="text" value="" placeholder="Username" id="username" name="username" />

    <input type="text" value="" placeholder="Email" id="Email" name="Email" />

    <input type="password" value="" placeholder="Password" id="password" name="password" />

    <input type="submit" id="signin" name="submit" />
</form>

<?php
include('connectivity.php');

if (mysqli_connect_errno())
  {
  echo "Failed to connect to mysqli: " . mysqli_connect_error();
  }
else 
{ 

}

function newUser()
{

include ('connectivity.php');

    $username = $_POST['username'];
    $username_escaped = mysqli_real_escape_string ($db, $username);

    $email = $_POST['email'];
    $email_escaped = mysqli_real_escape_string ($db, $email);

    $password = sha1($_POST['password']);
    $password_escaped = mysqli_real_escape_string ($db, $password);


    $query = "INSERT INTO users (username, email, password) VALUES ('$username_escaped', $email_escaped', '$password_escaped')";

    include('connectivity.php');
    $data = mysqli_query ($db, $query)or die(mysqli_error($db));
    if($data)
        {

    }

}

function SignUp()
{
    if(!empty($_POST['email']))
    {
        include('connectivity.php');
    $query = mysqli_query  ($db, "SELECT * FROM users WHERE email = '$_POST[email]'")
        or die(mysqli_error());
        if(!$row = mysqli_fetch_array($query))
        {
            newUser();
            echo ("<SCRIPT LANGUAGE='JavaScript'>
    window.alert('User Registration Successful')
    window.location.href='login.php';
    </SCRIPT>");

        } 
        else
        {
            echo ("<SCRIPT LANGUAGE='JavaScript'>
            window.alert('You are already a registered user!')
            window.location.href='homepage.html';
    </SCRIPT>");


        }
    }

}
if(isset($_POST['submit']))
    {
    SignUp();
}

?>

Register.php

<form class="form" action="register.php" method="POST" enctype="application/x-www-form-urlencoded">

    <input type="text" value="" placeholder="Username" id="username" name="username" />

    <input type="text" value="" placeholder="Email" id="Email" name="Email" />

    <input type="password" value="" placeholder="Password" id="password" name="password" />

    <input type="submit" id="signin" name="submit" />
</form>

<?php
include('connectivity.php');

if (mysqli_connect_errno())
  {
  echo "Failed to connect to mysqli: " . mysqli_connect_error();
  }
else 
{ 

}

function newUser()
{

include ('connectivity.php');

    $username = $_POST['username'];
    $username_escaped = mysqli_real_escape_string ($db, $username);

    $email = $_POST['email'];
    $email_escaped = mysqli_real_escape_string ($db, $email);

    $password = sha1($_POST['password']);
    $password_escaped = mysqli_real_escape_string ($db, $password);


    $query = "INSERT INTO users (username, email, password) VALUES ('$username_escaped', $email_escaped', '$password_escaped')";

    include('connectivity.php');
    $data = mysqli_query ($db, $query)or die(mysqli_error($db));
    if($data)
        {

    }

}

function SignUp()
{
    if(!empty($_POST['email']))
    {
        include('connectivity.php');
    $query = mysqli_query  ($db, "SELECT * FROM users WHERE email = '$_POST[email]'")
        or die(mysqli_error());
        if(!$row = mysqli_fetch_array($query))
        {
            newUser();
            echo ("<SCRIPT LANGUAGE='JavaScript'>
    window.alert('User Registration Successful')
    window.location.href='login.php';
    </SCRIPT>");

        } 
        else
        {
            echo ("<SCRIPT LANGUAGE='JavaScript'>
            window.alert('You are already a registered user!')
            window.location.href='homepage.html';
    </SCRIPT>");


        }
    }

}
if(isset($_POST['submit']))
    {
    SignUp();
}

?>

---

$\u post['email']
不存在，因为您已将
name
属性设置为
“email”


编辑：
我忘了提我回答的要点。姓名和$\u帖子区分大小写，因此
“email”！=“Email”
$\u post['Email']
不存在，因为您已将
名称
属性设置为
“Email”


编辑：
我忘了提我回答的要点。姓名和$\u帖子区分大小写，因此
“email”！=“电子邮件”
试试这个：

   $query = mysqli_query  ($db, "SELECT * FROM users WHERE email = '$email'") or die(mysqli_error($db));

试试这个：

   $query = mysqli_query  ($db, "SELECT * FROM users WHERE email = '$email'") or die(mysqli_error($db));

如果您再次查看，您将看到，是的，我已将name属性设置为email如果您再次查看，您将看到，是的，我已将name属性设置为email