Php 如何通过javascript函数调用codeigniter函数

这在我的codeigniter功能中不起作用。我有id，无法获取该id。请帮助我。这是我的视图，我正在尝试通过函数发送我的id

<script type="text/javascript">
    function makeajaxcall(id) {
        //alert(id);
        var r = confirm("Do you want to Delete");
        if (r == true) {
            window.location.href = "<?php echo site_url('controller_d/login/admin_link_delete_user?id='.id);?>";
        } else {
            x = "You pressed Cancel!";
            alert(x);
        }

    }
</script>

更改此行：

window.location.href = "<?php echo site_url('controller_d/login/admin_link_delete_user?id='.id);?>";

致：

试试这个

window.location.href = "<?php echo site_url('controller_d/login/admin_link_delete_user/'.id);?>";

---

使用ajax调用控制器函数。。。

window.location.href = "<?php echo site_url('controller_d/login/admin_link_delete_user/'.id);?>";

function admin_link_delete_user($id){
     echo $id;// u'll get the id which you are passing through javascript    
}

<script type="text/javascript">
function makeajaxcall(id)
{
      //alert(id);
      var r=confirm("Do you want to Delete");
      if (r==true)
      {
           $.post("<?php echo site_url('controller_d/login/admin_link_delete_user/');?>", {id:id},
           function(data) {
                alert(data+"a");
           }, 'json');
      }
      else
      {
           x="You pressed Cancel!";
           alert(x);
      }

}
</script>  

function admin_link_delete_user(){
   echo $this->input->post('id');
   //perform your code
}