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PHP和SQL(尝试使用提交按钮更新我的数据库)_Php_Html_Mysql - Fatal编程技术网

PHP和SQL(尝试使用提交按钮更新我的数据库)

PHP和SQL(尝试使用提交按钮更新我的数据库),php,html,mysql,Php,Html,Mysql,我正试图通过“提交”按钮更新我在SQL数据库表单中的反馈,但我无法这样做。请帮忙 if (isset($_POST['submitreport'])) { $dbCon = mysqli_connect("localhost","root","","Hun"); $report = strip_tags($_POST['report']); $sql = "UPDATE F

我正试图通过“提交”按钮更新我在SQL数据库表单中的反馈,但我无法这样做。请帮忙

if (isset($_POST['submitreport'])) 
            {
                $dbCon = mysqli_connect("localhost","root","","Hun");
                $report = strip_tags($_POST['report']);

                $sql = "UPDATE Feedback SET report='$report' WHERE username='$username' AND date='$date' ";

                $query = mysqli_query($dbCon, $sql);


            }

有错误吗?请提供更多详细信息。在$username=strip_标记($_POST['report'])中。对吗?报告为用户名提交后,报告列在数据库中没有更改。请使用$date条件检查。如果最后一个条件不匹配,它将不起任何作用是的,$date条件是正确的。@Kenneth:请设置$username变量的值。谢谢
    <?php
    if (isset($_POST['submitreport'])) 
    {
    $dbCon = mysqli_connect("localhost","root","","Hun");
    $username = 'test';
    $report = strip_tags($_POST['report']);
    $date = date('m-d-Y');

    $sql = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$date."'";

    $query = mysqli_query($dbCon, $sql);
    }
    ?>
<?php
      if (isset($_POST['submitreport'])) 

    {
       $monthDayYear = date('m-d-Y');

       $dbConnnection = mysqli_connect("localhost","root","","Hun");

       $dbUsername = strip_tags($_POST['report']);

       $sqlQuery = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$monthDayYear."'";

       $queryExecute = mysqli_query($dbConnection, $sqlQuery);


       }

    ?>