PHP和SQL(尝试使用提交按钮更新我的数据库)
我正试图通过“提交”按钮更新我在SQL数据库表单中的反馈,但我无法这样做。请帮忙PHP和SQL(尝试使用提交按钮更新我的数据库),php,html,mysql,Php,Html,Mysql,我正试图通过“提交”按钮更新我在SQL数据库表单中的反馈,但我无法这样做。请帮忙 if (isset($_POST['submitreport'])) { $dbCon = mysqli_connect("localhost","root","","Hun"); $report = strip_tags($_POST['report']); $sql = "UPDATE F
if (isset($_POST['submitreport']))
{
$dbCon = mysqli_connect("localhost","root","","Hun");
$report = strip_tags($_POST['report']);
$sql = "UPDATE Feedback SET report='$report' WHERE username='$username' AND date='$date' ";
$query = mysqli_query($dbCon, $sql);
}
有错误吗?请提供更多详细信息。在$username=strip_标记($_POST['report'])中。对吗?报告为用户名提交后,报告列在数据库中没有更改。请使用$date条件检查。如果最后一个条件不匹配,它将不起任何作用是的,$date条件是正确的。@Kenneth:请设置$username变量的值。谢谢
<?php
if (isset($_POST['submitreport']))
{
$dbCon = mysqli_connect("localhost","root","","Hun");
$username = 'test';
$report = strip_tags($_POST['report']);
$date = date('m-d-Y');
$sql = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$date."'";
$query = mysqli_query($dbCon, $sql);
}
?>
<?php
if (isset($_POST['submitreport']))
{
$monthDayYear = date('m-d-Y');
$dbConnnection = mysqli_connect("localhost","root","","Hun");
$dbUsername = strip_tags($_POST['report']);
$sqlQuery = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$monthDayYear."'";
$queryExecute = mysqli_query($dbConnection, $sqlQuery);
}
?>