获取PHP中的上一个URL路径
我试过这个获取PHP中的上一个URL路径,php,http,url,referrer,Php,Http,Url,Referrer,我试过这个 结果是http://localhost/index.php $previous_page = $_SERVER['HTTP_REFERER']; $path_parts = pathinfo($previous_page); $result = $path_parts['basename']; //index.php 如何仅获取index.php $previous_page = $_SERVER['HTTP_REFERER']; $path_parts = pathinfo($
结果是http://localhost/index.php
$previous_page = $_SERVER['HTTP_REFERER'];
$path_parts = pathinfo($previous_page);
$result = $path_parts['basename']; //index.php
如何仅获取index.php
$previous_page = $_SERVER['HTTP_REFERER'];
$path_parts = pathinfo($previous_page);
$result = $path_parts['basename']; //index.php
parse_url($\u SERVER['HTTP\u REFERER',PHP\u url\u PATH)
@Ja\866; ck这不是OP指定的内容。修剪前导斜杠是读者的练习,否则我会写一个答案;在任何情况下,都不清楚如果有更多的东西需要归还什么path@Ja͢对于不一致性,这是正确的。我道歉。