Php 返回表中的总行数

我可以像这样返回表中的行数吗，我得到了XML标记错误。

$output.=$row=mysql\u fetch\u array（$result）

将输出

array

也许您想要

$output.=mysql\u num\u rows（$result）？
您可以在php中使用函数count（$array）
在项目计数中需要什么？您必须在另一列上获取项目计数的位置编写查询（从整行获取数据，但在下一个查询中）。我无法在SP中使用我的计数。这就是我试图通过mysql_num_row获取总记录的原因。我想我们需要更多地了解您的代码，特别是您用来馈送$resultw的SQL查询xml输出是什么样子的？它是否有php错误或警告？
while($row=mysql_fetch_array($result))
{
    $output .= "<Reports>";

    $output .= "<ProjectName>";
    $output .= $row['ProjectName'];
    $output .= "</ProjectName>";

    $output .= "<ProjectCount>";
    $output .= $row=mysql_fetch_array($result)
    $output .= "</ProjectCount>";

    $output .= "</Reports>";
}

SELECT designation.desg_Name AS PM, project.ProjectName,
Case ProjectPhase.PhaseID WHEN 1 THEN 'ScopeofWork' END AS ScopeofWork,
Case ProjectPhase.PhaseID WHEN 2 THEN 'DesignDocument' END AS DesignDocument,
Case ProjectPhase.PhaseID WHEN 3 THEN 'Storyboard' END AS Storyboard,
Case ProjectPhase.PhaseID WHEN 4 THEN 'Alpha' END AS Alpha,
Case ProjectPhase.PhaseID WHEN 5 THEN 'Beta' END AS Beta,
Case ProjectPhase.PhaseID WHEN 6 THEN 'Gold' END AS Gold,
Case ProjectPhase.PhaseID WHEN 7 THEN 'TE Storyboard review' END AS 'TE Storyboard review'
FROM `tycodashboard` t JOIN project ON project.projectID = t.projectID
JOIN projectPhase ON projectPhase.PhaseID = t.PhaseID
JOIN designation ON designation.designationID = t.designationID