Php 使用不同的键完成数组

我从一些网站收到不同的json对象。 这些对象通常看起来不一样

如何在json对象的每个位置添加缺少的键

这里有一个示例来表示给定的对象

$data = new stdClass();
$data->a1 = ["name"=>"John","age"=>"27","phone"=>"5566634"];
$data->a2 = ["name"=>"Mark","age"=>"38","gender"=>"Male"];

这就是期望的输出：

$data->a1 = ["name"=>"John","age"=>"27","phone"=>"5566634", "gender"=>"unknown"];
$data->a2 = ["name"=>"Mark","age"=>"38","phone"=>"unknown", "gender"=>"Male"];

我只想在每个数组上都有相同的键

我尝试的是foreach所有对象并保存

$arraykeys

上的所有现有键。然后再次foreach所有对象，检查当前 键位于创建的

$arraykeys

中，但对于大型json对象来说，这非常缓慢

到目前为止，我一直试图得到所有的钥匙：

$arraykeys = [];
foreach ( $data as $item ) {
    foreach ( $item as $key => $value ) {
        if (! array_key_exists($key, $arraykeys)){
            $arraykeys[$key] = null;
        }
    }
}

但不知道如何完成拥有所有密钥的数组。我怎样才能解决这个问题

---

注意：对象可能具有

n

位置和更多关键点。这只是一个例子。理想情况下，每个数组上的键顺序相同。

如果要对多个字段执行此操作，可以执行以下操作：

<?php
$defaultArray = [
    'name'   => 'unknown',
    'age'    => 'unknown',
    'gender' => 'unknown',
    'phone'  => 'unknown',
];

foreach ( $data as $item ) {
    $item = array_merge($defaultArray, $item);
}

---

如果要对多个字段执行此操作，可以执行以下操作：

<?php
$defaultArray = [
    'name'   => 'unknown',
    'age'    => 'unknown',
    'gender' => 'unknown',
    'phone'  => 'unknown',
];

foreach ( $data as $item ) {
    $item = array_merge($defaultArray, $item);
}

使用
调用用户函数数组
，
数组替换递归
，
数组键
，
数组填充键
和
数组合并
函数的扩展解决方案：

$data = new stdClass();
$data->a1 = ["name"=>"John","age"=>"27","phone"=>"5566634"];
$data->a2 = ["name"=>"Mark","age"=>"38","gender"=>"Male"];
$data->a3 = ["name"=>"Mark","age"=>"38","gender"=>"Male", "email"=>"myemail@gmail.com", "address"=>"Jack London st. 102"];
$data->a4 = ["name"=>"John","age"=>"30","gender"=>"Male"];

// getting the array containing all possible keys
$keys = call_user_func_array('array_replace_recursive', (array) $data);

// filling predefined list of keys with "unknown" value
$keys = array_fill_keys(array_keys($keys), "unknown");

foreach ($data as &$prop) {
    $prop = array_merge($keys, $prop);
}

print_r($data);

输出：

stdClass Object
(
    [a1] => Array
        (
            [name] => John
            [age] => 27
            [phone] => 5566634
            [gender] => unknown
            [email] => unknown
            [address] => unknown
        )

    [a2] => Array
        (
            [name] => Mark
            [age] => 38
            [phone] => unknown
            [gender] => Male
            [email] => unknown
            [address] => unknown
        )

    [a3] => Array
        (
            [name] => Mark
            [age] => 38
            [phone] => unknown
            [gender] => Male
            [email] => myemail@gmail.com
            [address] => Jack London st. 102
        )

    [a4] => Array
        (
            [name] => John
            [age] => 30
            [phone] => unknown
            [gender] => Male
            [email] => unknown
            [address] => unknown
        )
)

使用
调用用户函数数组
，
数组替换递归
，
数组键
，
数组填充键
和
数组合并
功能的扩展解决方案：

$data = new stdClass();
$data->a1 = ["name"=>"John","age"=>"27","phone"=>"5566634"];
$data->a2 = ["name"=>"Mark","age"=>"38","gender"=>"Male"];
$data->a3 = ["name"=>"Mark","age"=>"38","gender"=>"Male", "email"=>"myemail@gmail.com", "address"=>"Jack London st. 102"];
$data->a4 = ["name"=>"John","age"=>"30","gender"=>"Male"];

// getting the array containing all possible keys
$keys = call_user_func_array('array_replace_recursive', (array) $data);

// filling predefined list of keys with "unknown" value
$keys = array_fill_keys(array_keys($keys), "unknown");

foreach ($data as &$prop) {
    $prop = array_merge($keys, $prop);
}

print_r($data);

输出：

stdClass Object
(
    [a1] => Array
        (
            [name] => John
            [age] => 27
            [phone] => 5566634
            [gender] => unknown
            [email] => unknown
            [address] => unknown
        )

    [a2] => Array
        (
            [name] => Mark
            [age] => 38
            [phone] => unknown
            [gender] => Male
            [email] => unknown
            [address] => unknown
        )

    [a3] => Array
        (
            [name] => Mark
            [age] => 38
            [phone] => unknown
            [gender] => Male
            [email] => myemail@gmail.com
            [address] => Jack London st. 102
        )

    [a4] => Array
        (
            [name] => John
            [age] => 30
            [phone] => unknown
            [gender] => Male
            [email] => unknown
            [address] => unknown
        )
)

“arraykeys”是一个预定义的列表吗？不，这只是一个示例，但还有更多的键，如电子邮件、地址等。将来可能还会更多。这就是为什么我需要获取所有密钥…@KrBm您可以使用您的解决方案来构建密钥阵列。信息技术works@KrBm或者，如果您使用“未知”初始化arraykeys，则可以稍微简化第二个循环——“arraykeys”是否被称为预定义列表？不，这只是一个示例，但还有更多的键，如电子邮件、地址等。将来可能还会更多。这就是为什么我需要获取所有密钥…@KrBm您可以使用您的解决方案来构建密钥阵列。信息技术works@KrBm或者，如果使用“未知”初始化arraykeys，则稍微简化第二个循环-看起来
手机
就在第一个数组上，我如何修复此问题？@KrBm抱歉，请稍候。将会有一个更新，例如
手机
就在第一个阵列上，我如何修复它？@KrBm抱歉，请稍等。将会有一个更新