我希望能够在JSON响应中提取属性的所有属性值，并将结果值添加到字符串（在PHP中）

我希望能够在JSON响应中提取STID属性的所有属性值，并将它们添加到PHP中的字符串，如12791280等

{ "tickets": { "ticket": { "STID": 1279, "CompanyID": 1000, "Status": 4, "Summary": "Things are broken", "Level": 2, "Closed": 0, "UserID": 34544, "TicketCode": 20130119-1279 } "ticket": { "STID": 1280, "CompanyID": 1000, "Status": 4, "Summary": "Things are broken", "Level": 2, "Closed": 0, "UserID": 34544, "TicketCode": 20130119-1279 } "ticket": { "STID": 1281, "CompanyID": 1000, "Status": 4, "Summary": "Things are broken", "Level": 2, "Closed": 0, "UserID": 34544, "TicketCode": 20130119-1279 } "ticket": { "STID": 1282, "CompanyID": 1000, "Status": 4, "Summary": "Things are broken", "Level": 2, "Closed": 0, "UserID": 34544, "TicketCode": 20130119-1279 } }

---

可以你被困在哪里？事实上，它告诉我们，有一个属性是这样指定的：TicketCode:20130119-1279。该值无效，需要用双引号括起来。好吧，我复制并粘贴了一个糟糕的示例：但关键是我希望能够将json响应中多次出现的属性的所有值提取到字符串中。我查询的json包含敏感/安全数据，因此我没有将其复制/粘贴到这里。