Php 动态SQL插入

我有一个PHP表单，它有许多字段。我想要的是动态地向查询添加字段，根据这些字段的内容在PostgreSQL表中插入值。如果一个字段（如date、int等）为空，我不希望它出现在查询中，因为当我试图插入到表中时，它会在等待插入值时导致“语法错误”。救命啊

编辑

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在mysql查询中定义变量名错误更改名称：

PHP变量的规则：

1) variable starts with the $ sign, followed by the name of the variable
2) variable name must start with a letter or the underscore character
3) **variable name cannot start with a number**
4) variable name can only contain alpha-numeric characters and underscores (A-z, 0-9, and _ )
Variable names are case sensitive ($y and $Y are two different variables)



$sql_insert = 'INSERT INTO hcd_customermeters ("meterSN", "contractCode", "deviceManufacturer", "deviceType", "firstInstallationDate", "diameter", "pipeID", "operatorCreator", "warehouseDeliveryDate", "recordCreation", "SRID") 
            VALUES ("'.$variableName."', "'.$variableName."', "'.$variableName."',"'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."',"'.$variableName."')';


mysql_query($sql_insert);

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如果有任何问题，请提一下。

听起来您的查询语法不正确。到目前为止你做了什么？你应该显示你正在构建的代码/查询，以便人们能够提供帮助。可能重复的裁缝，我检查了该链接，但我认为它不一样。那个家伙将字段添加到表中，而不是查询中。艾伦：到目前为止，我提出的问题是正确的。只是一个简单的插入。我想有一个单一的保存按钮，但所有字段都必须有值。如果不是，正如我所解释的，会出现语法错误。请用示例描述您的问题。您已经创建了表plz TINCE.Edited。表格准备好了，里面有记录。我的问题是当我尝试插入新记录时。上面的查询（在PHP中，这就是为什么$）运行正确。如果对应字段中没有pipeID的值，就会发生错误。它是一个预先准备好的语句，因此不需要转义或引用，并且值来自数组$参数=数组（…）；那不是我的问题所在。

1) variable starts with the $ sign, followed by the name of the variable
2) variable name must start with a letter or the underscore character
3) **variable name cannot start with a number**
4) variable name can only contain alpha-numeric characters and underscores (A-z, 0-9, and _ )
Variable names are case sensitive ($y and $Y are two different variables)



$sql_insert = 'INSERT INTO hcd_customermeters ("meterSN", "contractCode", "deviceManufacturer", "deviceType", "firstInstallationDate", "diameter", "pipeID", "operatorCreator", "warehouseDeliveryDate", "recordCreation", "SRID") 
            VALUES ("'.$variableName."', "'.$variableName."', "'.$variableName."',"'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."', "'.$variableName."',"'.$variableName."')';


mysql_query($sql_insert);