如何从PowerShell脚本调用Azure Devops任务？

我在存储库中有许多子文件夹，它们都包含Azure ARM模板（文件夹名称=资源组）

我试图迭代每个文件夹，然后从该文件夹的内容创建一个管道工件

如何从PowerShell脚本调用devops任务？下面的脚本给出一个错误，说明未找到

PublishPipelineArtifact

任务

foreach ($folder in (Get-ChildItem -Path $env:SYSTEM_DEFAULTWORKINGDIRECTORY -Directory -ErrorAction SilentlyContinue | Select-Object Name))
{
    Write-Host "Processing folder $($folder.Name)..."

    Write-Host "##vso[task.PublishPipelineArtifact targetPath=$folder;artifactName=$($folder.Name);]"

    Write-Host "Published artifact $($folder.Name)..."
}

---

不支持从PowerShell脚本调用devops任务，您可以尝试

每个

函数来循环

PublishPipelineArtifact

任务：

parameters:
- name: param
  type: object
  default:
  - folder1
  - folder2

 
steps:
  - ${{ each p in parameters.param }}:
      - task: PublishPipelineArtifact@1
        inputs:
          targetPath: '$(Pipeline.Workspace)' 
          artifactName: '${{ p }}'

---

我发现“记录命令”是可能的。看

例如，此脚本将所有文件夹打包为工件：

Write-Host ("Working folder is {0}" -f $($env:SYSTEM_DEFAULTWORKINGDIRECTORY))

foreach ($folder in (Get-ChildItem -Path $env:SYSTEM_DEFAULTWORKINGDIRECTORY -Directory -ErrorAction SilentlyContinue | Select-Object Name))
{
    Write-Host "Processing folder $($folder.Name)..."

    $folderPath = $env:SYSTEM_DEFAULTWORKINGDIRECTORY + "\" + $folder.Name
    $artifactFolder = $env:BUILD_ARTIFACTSTAGINGDIRECTORY + "\" + $folder.Name
    $pathToZip = $artifactFolder + "\" + $folder.Name + ".zip"

    Write-Host "Creating archive to " + $artifactFolder

    New-Item -ItemType directory -Path $artifactFolder

    $compress = @{
        Path = $($folderPath) + "\*"
        CompressionLevel = "Fastest"
        DestinationPath = $pathToZip
    }
    Compress-Archive @compress

    Write-Host "##vso[artifact.upload containerfolder=$($folder.Name);artifactname=$($folder.Name)_drop;]$pathToZip"

    Write-Host "Published artifact $($folder.Name)..."
}

---

这正是我一直在尝试使用yaml-each循环（如@Cece-Dong的回答中所示）所做的，但是如果要发布的文件夹列表是在运行时动态生成的，则不可能在生成列表之前，对表达式中的参数进行扩展，从而导致“预期序列或映射”分析管道时出错