在powershell脚本中强制立即求值(按值复制变量,而不是引用)
我对以下代码有问题在powershell脚本中强制立即求值(按值复制变量,而不是引用),powershell,powershell-2.0,Powershell,Powershell 2.0,我对以下代码有问题 foreach ($ex in ("foo", "bar", "baz")) { $timer = New-Object Timers.timer $taction = { Write-Host "Timer fired for: $ex" } $timer.Interval = 1000 $timer.AutoReset = $false $timer.Start() Register-ObjectEvent -InputObject $timer -Even
foreach ($ex in ("foo", "bar", "baz")) {
$timer = New-Object Timers.timer
$taction = {
Write-Host "Timer fired for: $ex"
}
$timer.Interval = 1000
$timer.AutoReset = $false
$timer.Start()
Register-ObjectEvent -InputObject $timer -EventName elapsed -SourceIdentifier "$ex" -Action $taction
}
此代码提供以下输出
Timer fired for: baz
Timer fired for: baz
Timer fired for: baz
但我想把它变成foo,bar和baz。问题似乎是$ex变量最终会被所有计时器读取,所以不管它有什么值,它们都会得到它。如何在$taction中复制$ex的值以使其唯一 尝试使用
[scriptblock]::Create()
,这将在创建时计算参数:
foreach ($ex in ("foo", "bar", "baz"))
{
$timer = New-Object Timers.timer
$taction = [scriptblock]::create("Write-Host Timer fired for: $ex")
$timer.Interval = 1000
$timer.AutoReset = $false
$timer.Start()
Register-ObjectEvent -InputObject $timer -EventName elapsed -SourceIdentifier $ex -Action $taction
}