Python 2.7 检查Python函数是否用特定的修饰符修饰
我想检查Python函数是否被修饰,并将修饰器参数存储在函数dict中。这是我的代码:Python 2.7 检查Python函数是否用特定的修饰符修饰,python-2.7,python-decorators,Python 2.7,Python Decorators,我想检查Python函数是否被修饰,并将修饰器参数存储在函数dict中。这是我的代码: from functools import wraps def applies_to(segment="all"): def applies(func): @wraps(func) def wrapper(*args, **kwargs): func.func_dict["segment"] = segment prin
from functools import wraps
def applies_to(segment="all"):
def applies(func):
@wraps(func)
def wrapper(*args, **kwargs):
func.func_dict["segment"] = segment
print func.__name__
print func.func_dict
return func(*args, **kwargs)
return wrapper
return applies
但看起来这条格言丢了:
@applies_to(segment="mysegment")
def foo():
print "Some function"
> foo() # --> Ok, I get the expected result
foo
{'segment': 'mysegment'}
> foo.__dict__ # --> Here I get empty result. Why is the dict empty?
{}
好的,多亏了他的线索,我找到了答案。即使有所改善
from functools import wraps
def applies_to(*segments):
def applies(func):
func.func_dict["segments"] = list(segments)
@wraps(func)
def wrapper(*args, **kwargs):
return func(*args, **kwargs)
return wrapper
return applies
谢谢 您在错误的时间修改了错误的函数。我是否应该在运行时修改“应用”函数?