Python 3.x 在python中搜索2D列表中的引用

我有一个2D列表，我正在尝试查找列表中单词“the”的出现情况

我正在自学python并尝试以下代码

data = [["the cat is fed", "the bar is barred", "cat is now a bar"],
        ["the cat was fed", "the bar was barred", "cat was now a bar"]]

whatIsTheSum = sum('the' in s for s in data)

print(whatIsTheSum)

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我希望结果为4，但程序返回0。

因为您没有迭代嵌套数组

whatIsTheSum = sum('the' in s for nested in data for s in nested)

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因为您没有迭代嵌套数组

whatIsTheSum = sum('the' in s for nested in data for s in nested)

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查找两个不同数组的元素。试试这个：

whatIsTheSum = sum('the' in s for s in data[0]+data[1])
print(whatIsTheSum)

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查找两个不同数组的元素。试试这个：

whatIsTheSum = sum('the' in s for s in data[0]+data[1])
print(whatIsTheSum)

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欢迎来到SO！如果其中一个字符串多次包含“the”，您的预期结果是什么<代码>在中只检查是否至少存在一个事件。欢迎使用SO！如果其中一个字符串多次包含“the”，您的预期结果是什么<在中的code>仅检查是否存在至少一个事件。