Python 3.x 如何从给定的句子中提取较长的字符串并忽略子字符串？

我有一个字符串列表和一个句子，如下所示：

list_of_strings=["skin allergy","hair loss","allergy","hair", "skin"]

sentence="She experienced skin allergy and hair loss after using it for 2-3 weeks"

我想将

列表\u字符串

与

句子

匹配，并仅将输出打印为较长的短语（忽略子字符串）：

我这样写的：但这会提取所有匹配的内容。

使用正则表达式

Ex:

import re

list_of_strings=["skin allergy","hair loss","allergy","hair", "skin"]
sentence="She experienced skin allergy and hair loss after using it for 2-3 weeks"
pattern = re.compile(r"(\b" + "|".join(list_of_strings) + r")\b")

m = pattern.findall(sentence)
print(m)

['skin allergy', 'hair loss']

输出：

import re

list_of_strings=["skin allergy","hair loss","allergy","hair", "skin"]
sentence="She experienced skin allergy and hair loss after using it for 2-3 weeks"
pattern = re.compile(r"(\b" + "|".join(list_of_strings) + r")\b")

m = pattern.findall(sentence)
print(m)

['skin allergy', 'hair loss']

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不要提供外部链接，请使用文本