Python 3.x Python Cerberus通过比较两个字段进行自定义验证
我有一个这样的模式Python 3.x Python Cerberus通过比较两个字段进行自定义验证,python-3.x,cerberus,Python 3.x,Cerberus,我有一个这样的模式 s = { "Field_1": { "type": "string", "required": True, "allowed": ["val_1", "val_2"], }, "Field_2": { "type&quo
s = {
"Field_1": {
"type": "string",
"required": True,
"allowed": ["val_1", "val_2"],
},
"Field_2": {
"type": "dict",
"required": True,
"schema": {
"from_dt": {"type": "date", "required": True, },
"upto_dt": {"type": "date", "required": True, },
},
},
}
class CustomValidator(cerberus.Validator):
types_mapping = cerberus.Validator.types_mapping.copy()
types_mapping["date"] = date_type
我使用一个自定义验证器来验证这样的日期类型
s = {
"Field_1": {
"type": "string",
"required": True,
"allowed": ["val_1", "val_2"],
},
"Field_2": {
"type": "dict",
"required": True,
"schema": {
"from_dt": {"type": "date", "required": True, },
"upto_dt": {"type": "date", "required": True, },
},
},
}
class CustomValidator(cerberus.Validator):
types_mapping = cerberus.Validator.types_mapping.copy()
types_mapping["date"] = date_type
我想通过cerberus向模式验证添加一个附加检查。我想确保字段2中的from_dt值小于字段2中的upto_dt值
如何在Python3中的Cerberus中执行此操作?您可以实现自定义规则或使用check\u with规则。这两个都在文档中描述。