Python 3.x 将两个数组连接为坐标对

我有两个numpy数组，需要组合成一个二维数组：每一行必须是一对坐标。例如，如果numpy数组是：

[1 2 3]
[a b c]

那么我的目标是：

[[1 a]
 [1 b]
 [1 c]
 [2 a]
 [2 b]
 [2 c]
 [3 a]
 [3 b]
 [3 c]]

我试过这个：

    import numpy as np

    x1_start, x1_stop, x1_step = 88.5, 91.5, 0.2
    x2_start, x2_stop, x2_step = 82, 90, 0.5

    x1 = np.arange(x1_start, x1_stop, x1_step)
    x2 = np.arange(x2_start, x2_stop, x2_step)

    x1x2 = np.array([])

    for k in range(len(x1)):
        for h in range(len(x2)):
            list = [x1[k], x2[h]]
            np.append(x1x2, list ,0)

x1x2 = []

for k in range(len(x1)):
    for h in range(len(x2)):
        x1x2.append([x1[k],x2[h]])

print(type(x1x2))
np.asarray(x1x2)
print(type(x1x2))

但结果是一个空的numpy数组。或者，我试过这样做：

    import numpy as np

    x1_start, x1_stop, x1_step = 88.5, 91.5, 0.2
    x2_start, x2_stop, x2_step = 82, 90, 0.5

    x1 = np.arange(x1_start, x1_stop, x1_step)
    x2 = np.arange(x2_start, x2_stop, x2_step)

    x1x2 = np.array([])

    for k in range(len(x1)):
        for h in range(len(x2)):
            list = [x1[k], x2[h]]
            np.append(x1x2, list ,0)

x1x2 = []

for k in range(len(x1)):
    for h in range(len(x2)):
        x1x2.append([x1[k],x2[h]])

print(type(x1x2))
np.asarray(x1x2)
print(type(x1x2))

---

该列表包含正确的数字，但当我打印其类型时，结果是np.array cast前后的列表。

单向

meshgrid

x = np.array([1,2,3])
y = np.array([4,5,6])
np.array(np.meshgrid(x, y)).T.reshape(-1, 2)

将导致

array([[1, 4],
       [1, 5],
       [1, 6],
       [2, 4],
       [2, 5],
       [2, 6],
       [3, 4],
       [3, 5],
       [3, 6]])

meshgrid

对所有可能的组合进行配对，转换以将它们组合在一起，然后根据需要进行重塑