python类如何用不同的名称初始化？

昨天我不得不在python项目中使用WMI。我找到了python库。 这个库有很好的文档记录，有很多工作示例。e、 g:

import wmi
c = wmi.WMI ()

for process in c.Win32_Process ():
  print process.ProcessId, process.Name

或

我很好奇我可以为WMI类初始化传递什么样的参数，并查看了源代码。我在寻找类似于类WMI:或函数def WMI（），但我发现它是这样声明的：

#
# class WMI
#
class _wmi_namespace:
  """A WMI root of a computer system. The classes attribute holds a list
  of the classes on offer. This means you can explore a bit with
  things like this::

    c = wmi.WMI ()
    for i in c.classes:
      if "user" in i.lower ():
        print i
  """
  def __init__ (self, namespace, find_classes):
    _set (self, "_namespace", namespace)
    #
    # wmi attribute preserved for backwards compatibility
    #
    _set (self, "wmi", namespace)

    self._classes = None
    self._classes_map = {}
    #
    # Pick up the list of classes under this namespace
    #  so that they can be queried, and used as though
    #  properties of the namespace by means of the __getattr__
    #  hook below.
    # If the namespace does not support SubclassesOf, carry on
    #  regardless
    #
    if find_classes:
      _ = self.classes

---

正如我看到的，在注释中有一个解释它是如何工作的，但无论如何我都无法理解。

WMI

定义为

WMI.py

中第1295行周围的

WMI=connect

，它不是一个类，而是

connect（）

函数的另一个名称。

---

因此，要查看参数，请查看

connect（）

（请记住Python是区分大小写的）

#
# class WMI
#
class _wmi_namespace:
  """A WMI root of a computer system. The classes attribute holds a list
  of the classes on offer. This means you can explore a bit with
  things like this::

    c = wmi.WMI ()
    for i in c.classes:
      if "user" in i.lower ():
        print i
  """
  def __init__ (self, namespace, find_classes):
    _set (self, "_namespace", namespace)
    #
    # wmi attribute preserved for backwards compatibility
    #
    _set (self, "wmi", namespace)

    self._classes = None
    self._classes_map = {}
    #
    # Pick up the list of classes under this namespace
    #  so that they can be queried, and used as though
    #  properties of the namespace by means of the __getattr__
    #  hook below.
    # If the namespace does not support SubclassesOf, carry on
    #  regardless
    #
    if find_classes:
      _ = self.classes