如何在Python中将数组（二维列表）分配给dict？

我想给字典分配一个数组（列表中的列表）

为此，我已经尝试了fromkeys（）方法。但这并不像我预期的那样有效

# a list with 3 string elements
list_of_Strings = ['index', 'substance', 'container']
# a list with 3 lists, each list has a few values
index_list = [0,1,2]
substance_list = ['water','oil','acetone']
container_list = ['B100','B200','B300']
list_of_lists = [index_list, substance_list, container_list]

# this line sets all for all dict keys the value to 0
dict_dummy_1 = dict.fromkeys(list_of_Strings,0)

# when I try this line, in every "key value" are all 3 lists from list_of_lists:
# Key -> Value
# index -> index_list, substance_list, container_list
# substance -> index_list, substance_list, container_list
# container -> index_list, substance_list, container_list
dict_dummy_1 = dict.fromkeys(list_of_Strings,list_of_lists)

# but I want to have it like this:
# Key -> Value
# index -> index_list
# substance -> substance_list
# container -> container_list

# with a loop it is possible:
dict_dummy_2 = dict.fromkeys(list_of_Strings,0)
for i in range(len(list_of_Strings)):
    dict_dummy_2[list_of_Strings[i]] = list_of_lists[i]

是否有可能避免循环解决方案？它有什么功能吗？

---

提前非常感谢。：）

您可以使用听写理解：

{list_of_Strings[i]: list_of_lists[i] for i in range(len(list_of_Strings))}

---

下面是一个使用zip的简单oneliner：

dict(zip(list_of_Strings,list_of_lists))

输出

{'index': [0, 1, 2],
 'substance': ['water', 'oil', 'acetone'],
 'container': ['B100', 'B200', 'B300']}

---

或者

{key:value for key，value in zip（字符串列表，列表列表）}

您可以添加最终输出吗

{'index': [0, 1, 2],
 'substance': ['water', 'oil', 'acetone'],
 'container': ['B100', 'B200', 'B300']}