Python Django URL正则表达式

我在为django应用程序定义URL时遇到问题

我想要它，这样当我打字时

我能读一篇文章

我可以编辑一篇文章

目前，我对它的定义如下：

url(r'^post/(?P<id>\d+)/edit/$',
    'board.views.edit_post',
    name='edit_post'),

url(r'^post/(?P<id>\d+)',
    'board.views.view_post',
    name='view_post'),

及

---

好吧，我建议您开始使用基于类的视图，另外，为什么不呢。可以让你的生活更轻松，大多数时候，你写得更少

class UpdatePost(UpdateView):
    model = Post # assuming you've made from your_app.models import Post call already
    fields = ['title', 'content', 'pub_date'] # for demonstration purposes
    template_name = 'post_form.html'

    @method_decorator(login_required) #Use login required on your dispatch method
    def dispatch(self, request, *args, **kwargs):
        pulled = Post.objects.get(id=kwargs['id']) 
        if pulled.created_by == request.user: #just to verify person making edit is rightly disposed to do so
            return super(UpdatePost, self).dispatch(request, *args, **kwargs)
        raise PermissionDenied

像这样在你的url中甜蜜地截取id

url(r'^app/edit/(?P<id>\d+)/$', views.UpdatePost.as_view(), name='edit'),

---

我就是这样做的。我从我的工作项目中提取了这个，但是还没有测试这个经过调整的版本。但是它应该可以工作。

确定视图函数的命名正确吗？这些路线看起来不错。当你最后用/尝试时会发生什么？例如：/post/{{post.id}}/edit/hmm，这很奇怪。。在这种情况下，让我添加我的view\u post和edit\u postviews@GustavoMeiraI get:AttributeError at/post/5/edit/和“tuple”对象没有属性“get”，因为您错过了在edit\u post结束时渲染的调用：您只是直接返回参数。

class UpdatePost(UpdateView):
    model = Post # assuming you've made from your_app.models import Post call already
    fields = ['title', 'content', 'pub_date'] # for demonstration purposes
    template_name = 'post_form.html'

    @method_decorator(login_required) #Use login required on your dispatch method
    def dispatch(self, request, *args, **kwargs):
        pulled = Post.objects.get(id=kwargs['id']) 
        if pulled.created_by == request.user: #just to verify person making edit is rightly disposed to do so
            return super(UpdatePost, self).dispatch(request, *args, **kwargs)
        raise PermissionDenied

url(r'^app/edit/(?P<id>\d+)/$', views.UpdatePost.as_view(), name='edit'),