R包Rssa没有使用rpy2 importr导入到python中

当我用Python命令执行时

rssa = importr('Rssa')

我得了性欲

Traceback (most recent call last):
  File "<pyshell#3>", line 1, in <module>
    rssa = importr('Rssa')
  File "C:\Python34\lib\site-packages\rpy2\robjects\packages.py", line 412, in importr
    version = version)
  File "C:\Python34\lib\site-packages\rpy2\robjects\packages.py", line 178, in __init__
    self.__fill_rpy2r__(on_conflict = on_conflict)
  File "C:\Python34\lib\site-packages\rpy2\robjects\packages.py", line 280, in __fill_rpy2r__
    super(SignatureTranslatedPackage, self).__fill_rpy2r__(on_conflict = on_conflict)
  File "C:\Python34\lib\site-packages\rpy2\robjects\packages.py", line 233, in __fill_rpy2r__
    rpyobj = conversion.ri2ro(riobj)
  File "C:\Python34\lib\functools.py", line 707, in wrapper
    return dispatch(args[0].__class__)(*args, **kw)
  File "C:\Python34\lib\site-packages\rpy2\robjects\__init__.py", line 101, in _
    return SignatureTranslatedFunction(obj)
  File "C:\Python34\lib\site-packages\rpy2\robjects\functions.py", line 150, in __init__
    raise ValueError("Error: '%s' already in the translation table. This means that the signature of the R function contains the parameters '%s' and/or '%s' <sigh> in multiple copies." %(r_param, r_param, prm_translate[py_param]))
ValueError: Error: '...' already in the translation table. This means that the signature of the R function contains the parameters '...' and/or '...' <sigh> in multiple copies.

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我在寻找这样的问题，但我找不到任何接近的。请对此问题提出一些建议。

这是由于Rssa试图控制“分解”功能（从“stats”包导出）时出现错误造成的。特别是，在形式列表中，“…”被添加了两次，这正是rpy2所抱怨的

这将在随后的Rssa版本中修复

唯一的解决方法是在R/common.R中注释掉以下行：

formals(decompose.default) <- c(formals(decompose.default), alist(... = ))

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formals（decompose.default）非常感谢，安东。我会尽量这样做。
formals(decompose.default) <- c(formals(decompose.default), alist(... = ))