Python scipy interp1d中的错误

我不理解interp1d报告的结果。我在应该接收数字的地方接收NAN

In [131]: bb
Out[131]: 
array([ 0.        ,  1.80286595,  1.87443683,  2.70410611,  3.02764722,
        3.11305985,  3.11534355,  3.18695351,  3.20693444])

In [132]: alphas1
Out[134]: 
array([  3.80918778e+00,   2.06547222e+00,   1.99234191e+00,
         7.55942418e-01,   2.56971574e-01,   1.05144676e-01,
         9.30852046e-02,   1.52574183e-02,   1.23664407e-07])

In [135]: bb.shape
Out[135]: (9,)

In [136]: alphas1.shape
Out[140]: (9,)

In [141]: pol = interp1d(alphas1, bb, bounds_error=False)

In [149]: pol(pol.x)
Out[149]: array([ nan,  nan,  nan,  nan,  nan,  nan,  nan,  nan,  nan]) # I was expecting to receive nan only at the borders.

---

我认为，如果您检查

interp1d

类的方法，即

\u check\u bounds

方法，可以看出问题：

def _check_bounds(self, x_new):

    ...

    below_bounds = x_new < self.x[0]
    above_bounds = x_new > self.x[-1]

    # !! Could provide more information about which values are out of bounds
    if self.bounds_error and below_bounds.any():
        raise ValueError("A value in x_new is below the interpolation "
            "range.")
    if self.bounds_error and above_bounds.any():
        raise ValueError("A value in x_new is above the interpolation "
            "range.")

---

现在，

alphas1

将如scipy所预期的那样增加，

pol（pol.x）

将按预期返回

bb

。

哪个版本？给出了

scipy 0.14.0中
np.array（[3.20693444，3.18695351，…
in[25]：np.version.version Out[29]：[30]：scipy.version.version Out[44]：“0.13.3”Update
scipy
中的
numpy 1.8.1
的正确答案，它可能会消失。谢谢，它没有工作！
bb = bb[::-1]
alphas1 = alphas[::-1]
pol = interp1d(alphas1, bb, bounds_error=False)