如何在python中反转子列表
鉴于以下清单:如何在python中反转子列表,python,python-3.x,list,Python,Python 3.x,List,鉴于以下清单: a = ['aux iyr','bac oxr','lmn xpn'] c = [] for i in a: x = i.split(" ") b= x[1][::-1] --- Got stuck after this line 有谁能帮我把它加入到实际的列表中,并带来预期的输出 输出=['aux ryi','bac rxo','lmn npx']我认为您需要两行代码,首先拆分值: b = [x.split() for x in a]
a = ['aux iyr','bac oxr','lmn xpn']
c = []
for i in a:
x = i.split(" ")
b= x[1][::-1] --- Got stuck after this line
有谁能帮我把它加入到实际的列表中,并带来预期的输出
输出=['aux ryi','bac rxo','lmn npx']我认为您需要两行代码,首先拆分值:
b = [x.split() for x in a]
返回:
[['aux', 'iyr'], ['bac', 'oxr'], ['lmn', 'xpn']]
['aux ryi', 'bac rxo', 'lmn npx']
然后恢复顺序:
output = [x[0] +' '+ x[1][::-1] for x in b]
返回:
[['aux', 'iyr'], ['bac', 'oxr'], ['lmn', 'xpn']]
['aux ryi', 'bac rxo', 'lmn npx']
您可以使用以下简单理解:
[" ".join((x, y[::-1])) for x, y in map(str.split, a)]
# ['aux ryi', 'bac rxo', 'lmn npx']
每个字符串是否有两个以上的令牌?如果是,第二个令牌之后会发生什么?