Python 从列表列表中创建列表，对枚举方法创建的每个列表使用相同的重复索引号

我的函数desired_headers（）从“results”对象中删除元组，元组中的第一个元素与headers列表中的任何字符串都不匹配<代码>['Fish'，'Dolphin']来自result1对象&

['Local Auth'，'bucket']

已从result3中删除

然后它打印索引号和元组列表，如下面的CurrentOutput下所示

我的目标是使用当前输出“重新打包”元组列表并存储在对象中

headers2 = ['Group', 'Owner', 'Person in charge', 'Type of Service',
                    'Registered Care Categories*', 'Specialist Care Categories',
                    'Languages Spoken by Staff (other than English)','Single Rooms', 
                    'Shared Rooms','Facilities & Service']


result1 = [['Group', 'MacIntyre'], ['Person in charge', ' Vivienne Donald (Manager)'],
           ['Type of Service', 'good'], ['Fish', 'Dolphin'], ['Shared Rooms', '4']]

result2 = [['Group', 'Jameseson'], ['Type of Service', 'bad'], ['Shared Rooms', '8']]

result3 = [['Group', 'MacIntyre'], ['Person in charge', ' Vivienne Donald (Manager)'],
           ['Type of Service', 'good'], ['Shared Rooms', '4'], ['Local Auth', 'bucket']]

results = [result1, result2, result3]

#Removes tuples which the first element in the tuple does not matcch any string in headers2 list
def desired_headers():
  for index, z in enumerate(list(range(len(results)))):
     for i in list(range(len(results[z]))):
       if any(x in headers2 for x in results[z][i]):  
           print(index, results[z][i])



desired_headers()

电流输出：

0 ['Group', 'MacIntyre']
0 ['Person in charge', ' Vivienne Donald (Manager)']
0 ['Type of Service', 'good']
0 ['Shared Rooms', '4']
1 ['Group', 'Jameseson']
1 ['Type of Service', 'bad']
1 ['Shared Rooms', '8']
2 ['Group', 'MacIntyre']
2 ['Person in charge', ' Vivienne Donald (Manager)']
2 ['Type of Service', 'good']
2 ['Shared Rooms', '4']

期望输出：

[[['Group', 'MacIntyre'],
  ['Person in charge', ' Vivienne Donald (Manager)'],
  ['Type of Service', 'good'],
  ['Shared Rooms', '4']],
 [['Group', 'Jameseson'], ['Type of Service', 'bad'], ['Shared Rooms', '8']],
 [['Group', 'MacIntyre'],
  ['Person in charge', ' Vivienne Donald (Manager)'],
  ['Type of Service', 'good'],
  ['Shared Rooms', '4']]]

---

你需要这样的东西吗？这将在单个列表中对所有内容进行分组

# Removes tuples which the first element in the tuple does not matcch any string in headers2 list
def desired_headers():
    grouped_elements = []
    for index, z in enumerate(list(range(len(results)))):
        inner_loop = []
        for i in list(range(len(results[z]))):
            if any(x in headers2 for x in results[z][i]):
                inner_loop.append(results[z][i])

        grouped_elements.append(inner_loop)

    print(grouped_elements)

---

你需要这样的东西吗？这将在单个列表中对所有内容进行分组

# Removes tuples which the first element in the tuple does not matcch any string in headers2 list
def desired_headers():
    grouped_elements = []
    for index, z in enumerate(list(range(len(results)))):
        inner_loop = []
        for i in list(range(len(results[z]))):
            if any(x in headers2 for x in results[z][i]):
                inner_loop.append(results[z][i])

        grouped_elements.append(inner_loop)

    print(grouped_elements)

试试这个

lv1 = [] # initialize an empty list which we will append to based on our criteria

for lst in results: # loop though each element of the list, which itself is a list
    lv2 = []
    for el in lst: # Same as above
        if el[0] in headers2: # check if first element of the list exists in headers2
            lv2.append(el)
    lv1.append(lv2)

lv1

或者如果你想要一个函数

def desired_headers(list_of_lists, inclution_list):
    lv1 = []

    for lst in list_of_lists:
        lv2 = []
        for el in lst:
            if el[0] in inclution_list:
                lv2.append(el)
        lv1.append(lv2)

    return lv1

desired_headers(list_of_lists=[result1, result2, result3], inclution_list=headers2)

或者如果你熟悉列表的理解

result = [] 

for lst in [result1, result2, result3]:
    result.append([el for el in lst if el[0] in headers2])

result 

试试这个

lv1 = [] # initialize an empty list which we will append to based on our criteria

for lst in results: # loop though each element of the list, which itself is a list
    lv2 = []
    for el in lst: # Same as above
        if el[0] in headers2: # check if first element of the list exists in headers2
            lv2.append(el)
    lv1.append(lv2)

lv1

或者如果你想要一个函数

def desired_headers(list_of_lists, inclution_list):
    lv1 = []

    for lst in list_of_lists:
        lv2 = []
        for el in lst:
            if el[0] in inclution_list:
                lv2.append(el)
        lv1.append(lv2)

    return lv1

desired_headers(list_of_lists=[result1, result2, result3], inclution_list=headers2)

或者如果你熟悉列表的理解

result = [] 

for lst in [result1, result2, result3]:
    result.append([el for el in lst if el[0] in headers2])

result 

---

您可以通过列表来完成：

filtered = [ [sl for sl in r if sl[0] in headers2] for r in results ]

输出：

print(filtered)

[
    [
        ['Group', 'MacIntyre'],
        ['Person in charge', ' Vivienne Donald (Manager)'],
        ['Type of Service', 'good'],
        ['Shared Rooms', '4']
    ],
    [
        ['Group', 'Jameseson'],
        ['Type of Service', 'bad'],
        ['Shared Rooms', '8']
    ],
    [
        ['Group', 'MacIntyre'],
        ['Person in charge', ' Vivienne Donald (Manager)'],
        ['Type of Service', 'good'],
        ['Shared Rooms', '4']
    ]
]

---

如果您有大量数据，您可能需要列出一组

标题2

，用于列表理解您可以使用列表理解：

filtered = [ [sl for sl in r if sl[0] in headers2] for r in results ]

输出：

print(filtered)

[
    [
        ['Group', 'MacIntyre'],
        ['Person in charge', ' Vivienne Donald (Manager)'],
        ['Type of Service', 'good'],
        ['Shared Rooms', '4']
    ],
    [
        ['Group', 'Jameseson'],
        ['Type of Service', 'bad'],
        ['Shared Rooms', '8']
    ],
    [
        ['Group', 'MacIntyre'],
        ['Person in charge', ' Vivienne Donald (Manager)'],
        ['Type of Service', 'good'],
        ['Shared Rooms', '4']
    ]
]

---

如果你有很多数据，你可能想把

headers2

放在列表理解中

在

中用作索引，z在枚举中（列表（范围（len（results）））

索引和z值作为旁白，不要使用

列表（范围（…）

只是

范围（…）

元组是一个没有两个项的列表。您拥有的是一个列表列表。在索引的

中，枚举中的z（范围（len（results））

索引和z值与旁白相同，不要使用

列表（范围（…）

仅

范围（…）

元组是一个不包含两项的列表。你拥有的是一个列表列表。