如何使用python argparse创建互斥选项组？

python argparse模块提供互斥选项组“add_mutual_exclusive_group”，使概要如下所示：

'script.py [-a | -b]'

Example: script.py -a is valid, script.py -a -b is invalid.

'script.py [[-a | -b] | [-c | -d]]'

Example: script.py -a is valid, script.py -c -d is invalid, script.py -a -c is invalid.

'script.py [mode1 -a -b| mode2 -c -d]'

Example: script.py mode1 -a -b is valid, script.py mode1 -a -c is invalid.

我找到了一种创建互斥组的方法，互斥组的外观如下：

'script.py [-a | -b]'

Example: script.py -a is valid, script.py -a -b is invalid.

'script.py [[-a | -b] | [-c | -d]]'

Example: script.py -a is valid, script.py -c -d is invalid, script.py -a -c is invalid.

'script.py [mode1 -a -b| mode2 -c -d]'

Example: script.py mode1 -a -b is valid, script.py mode1 -a -c is invalid.

我还了解了子命令，它们看起来是这样的：

'script.py [-a | -b]'

Example: script.py -a is valid, script.py -a -b is invalid.

'script.py [[-a | -b] | [-c | -d]]'

Example: script.py -a is valid, script.py -c -d is invalid, script.py -a -c is invalid.

'script.py [mode1 -a -b| mode2 -c -d]'

Example: script.py mode1 -a -b is valid, script.py mode1 -a -c is invalid.

我没有找到但非常想要的是：

'script.py [-a -b | -c -d]'

Example: script.py -a -b is valid, script.py -a -c is invalid.

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argparse支持这一点吗？

在互斥组中没有嵌套组的方法（使用“any”或“all”逻辑）。即使您的第二个示例实际上也是一个扁平的

xor

组-只允许4个组中的一个script.py[-a |-b |-c |-d]'