Python 如何使用Flask让用户在帖子中发布音乐文件?
我的网站将允许用户发布类似于博客文章的内容,但附带一个音频文件,以便其他用户可以在阅读时收听。我做了一个虚拟的帖子,这样我可以检查一些东西和一条简单的路线Python 如何使用Flask让用户在帖子中发布音乐文件?,python,flask,Python,Flask,我的网站将允许用户发布类似于博客文章的内容,但附带一个音频文件,以便其他用户可以在阅读时收听。我做了一个虚拟的帖子,这样我可以检查一些东西和一条简单的路线 from flask import render_template from site import app posts = [{ 'title': 'asdf', 'text': 'asdf', 'file': "2.mp3" }] @app.route("/") @ap
from flask import render_template
from site import app
posts = [{
'title': 'asdf',
'text': 'asdf',
'file': "2.mp3"
}]
@app.route("/")
@app.route("/home")
def home():
return render_template('home.html', posts=posts)
我还有home.html模板
<!DOCTYPE html>
<html>
<head>
<title>Site</title>
</head>
<body>
{% for post in posts %}
<h1>
{{ post.title }}
</h1>
<h2>
{{ post.text }}
</h2>
<audio controls>
<source src="{{ post.file }}" type="audio/mpeg">
</audio>
{% endfor %}
</body>
</html>
场地
{posts%%中的post为%s}
{{post.title}}
{{post.text}
{%endfor%}
我的逻辑很简单:如果2.mp3文件与home.html文件位于同一目录中,那么音乐应该播放。但事实并非如此。我真的不知道该怎么办。我使用的是Python3.7。这实际上比那要复杂一些,因为它们有两个选项 第一个是“简单的一个”,以及你想要达到的目标。将文件与主模板一起放在
静态
文件夹中,并通过模板将其返回给用户
要实现这一点,您只需稍微修改一下模板:
<source src="{{ url_for('static', filename=post.file) }}" type="audio/mpeg">
import os
from flask import Flask, flash, request, redirect, url_for
from werkzeug.utils import secure_filename
from flask import send_from_directory
UPLOAD_FOLDER = '/path/to/the/uploads'
ALLOWED_EXTENSIONS = {'txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif', '.mp3'}
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
if request.method == 'POST':
# check if the post request has the file part
if 'file' not in request.files:
flash('No file part')
return redirect(request.url)
file = request.files['file']
# if user does not select file, browser also
# submit an empty part without filename
if file.filename == '':
flash('No selected file')
return redirect(request.url)
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
return redirect(url_for('uploaded_file',
filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form method=post enctype=multipart/form-data>
<input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
return send_from_directory(app.config['UPLOAD_FOLDER'],
filename)