Python 在一定范围内对列表进行四舍五入

我有一个数字列表，我希望以某种方式转换为单位步骤形式

这就是我的界限

[367.3090551181102, 371.73179133858264, 376.1545275590551, 380.5772637795276, 385.0]

这是我掌握的数据

[367.3090551181102, 370, 370, 370, 370, 370, 370, 370, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 368, 369, 368, 368, 368, 368, 368, 368, 368, 368, 369, 370, 367.3090551181102, 367.3090551181102, 367.3090551181102, 370, 368, 373, 369, 371, 368, 367.3090551181102, 367.3090551181102, 367.3090551181102, 369, 367.3090551181102, 372, 367.3090551181102, 368, 368, ...]

我想做的是基本上把数据中的每个数字向下或向上舍入到边界。数字介于下边界和上边界之间

假设数字是370，我想把它四舍五入到371.73。。。因为它在367.309之间。。。和371.73。。。或者数字是381，然后我想把它四舍五入到370.57

这是我的代码，但我有点困惑

def unit_step(data,boundaries):
    us = []
    for d in data:
        if(boundaries[0] < d < boundaries[1]):
            us.append(rounder(boundaries[0],boundaries[1],d))
        elif(boundaries[1] < d < boundaries[2]):
            us.append(rounder(boundaries[1],boundaries[2],d))
        elif(boundaries[2] < d < boundaries[3]):
            us.append(rounder(boundaries[2],boundaries[3],d))
        elif(boundaries[3] < d < boundaries[4]):
            us.append(rounder(boundaries[3],boundaries[4],d))
    return us

def装置步骤（数据、边界）：
美国=[]
对于数据中的d：
如果（边界[0]

我在另一个for循环中尝试了for循环，但没有成功

---

与double for loop相比，我哪里错了，或者这是一种有用的方法？

您可以使用

min

的列表理解来检查

边界中最近的（较高或较低的）值，并相应地替换
数据中的值

>>> [min(boundaries, key=lambda i: abs(i - value)) for value in data]
[367.3090551181102, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102]

您可以使用列表理解和
min
检查
边界中最近的（较高或较低的）值，并相应地替换
数据中的值

>>> [min(boundaries, key=lambda i: abs(i - value)) for value in data]
[367.3090551181102, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102]

这回答了你的问题吗@MadyDaby不不是我要找的那个这个能回答你的问题吗@MadyDaby不是我要找的那个