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如何在mongoengine python中聚合组_Python_Django_Mongodb_Mongoengine - Fatal编程技术网

如何在mongoengine python中聚合组

如何在mongoengine python中聚合组,python,django,mongodb,mongoengine,Python,Django,Mongodb,Mongoengine,我正在尝试在MongoDB中聚合group 我们正在使用Python、django、Rest框架和Mongoengine 我的模型是这样的: class TestSnapshot(EmbeddedDocument): identifier = StringField() name = StringField() created = DateTimeField( default = datetime.datetime.now) class Test(Document):

我正在尝试在
MongoDB
中聚合
group

我们正在使用
Python
django
Rest框架
Mongoengine

我的模型是这样的:

class TestSnapshot(EmbeddedDocument):
    identifier = StringField()
name = StringField()
created = DateTimeField(
    default = datetime.datetime.now)

class Test(Document):
    agreement = ReferenceField(Agreement)
history = ListField(EmbeddedDocumentField(TestSnapshot))
created = DateTimeField(
    default = datetime.datetime.now)
我认为:

test = models.Test.objects.filter(agreement__in = agreements).aggregate([{
    "$unwind": "$created"
}, {
    "$group": {
    "_id": "$created"
    }
}])
print test
但我有这样的追踪:

OperationFailure: command SON([('aggregate', u 'test'), ('pipeline', [{
    '$match': {
        'agreement': {
            '$in': [ObjectId('558b150a89f4ad3f33ebb8ae')]
        }
    }
    },
    [{
    '$unwind': '$created'
    }, {
    '$group': {
        '_id': '$created'
    }
    }]
]), ('cursor', {})]) on namespace noq.$cmd failed: exception: pipeline element 1 is not an object
我做错了什么?我不熟悉
python
mongo
。 谢谢你的帮助:)

致以最良好的祝愿,
约翰尼

我已经解决了这个问题,我做错了

models.Test.objects.filter(agreement__in = agreements).aggregate(
  {"$group": { "_id": "$created" }}
)

无论如何,谢谢:)

您尝试了聚合中的列表。这是个错误。如果可以的话,你可以给出广泛的答案。这将帮助其他人。